在程序中使用兩個不同的同一類的堆棧時出現分段錯誤

Question

我剛剛啓動了C++並編寫了一個程序，以同時在兩個堆棧中推送和彈出一個程序......我編寫了正確的代碼，但是當我運行該程序並嘗試訪問，即S1是第一個堆棧顯示分段錯誤，但我能訪問我的第二堆S2非常完美.....幫我

#include<iostream> 
using namespace std; 
#define max 10 
class stack 
{ 
private: 
    int arr[max],top; 
public: 
    void init() 
    { 
     int top=0; 
    } 
    void push(int a) 
    { 
     arr[top++]=a; 
    } 
    int pop() 
    { 
     return arr[--top]; 
    } 
    int isempty() 
    { 
     if(top==0) 
      return 1; 
     else 
      return 0; 
    } 
    int isfull() 
    { 
     if(top==max) 
      return 1; 
     else 
      return 0; 
    } 
}; 
int main() 
{ 
    int a,z,cas; 
    stack s1; 
    stack s2; 
    s1.init(); 
    s2.init(); 
    while(1) 
    { 
     cout<<"Enter your choice i.e. :\n"; 
     cout<<"1.Pushing in stack s1.\n"; 
     cout<<"2.Pushing in stack s2.\n"; 
     cout<<"3.Poping from stack s1.\n"; 
     cout<<"4.Poping from stack s2.\n"; 
     cout<<"5.To STOP.\n"; 
     cin>>cas; 
     switch(cas) 
     { 
     case 1: 
      cout<<"Enter the number to push in stack s1:\n"; 
      cin>>a; 
      if(s1.isfull()==0) 
       s1.push(a); 
      else 
       cout<<"The Stack is full.\n"; 
      break; 
     case 2: 
      cout<<"Enter the number to push in stack s2:\n"; 
      cin>>a; 
      if(s2.isfull()==0) 
       s2.push(a); 
      else 
       cout<<"The Stack is full.\n"; 
      break; 
     case 3: 
      if(s1.isempty()==0) 
       cout<<"The number poped out is :\n"<<s1.pop()<<endl; 
      else 
       cout<<"The stack is empty.\n"; 
      break; 
     case 4: 
      if(s2.isempty()==0) 
       cout<<"The number poped out is :\n"<<s2.pop()<<endl; 
      else 
       cout<<"The stack is empty.\n"; 
      break; 
     case 5: 
      cout<<"The elements in stack s1 are :\n"; 
      while(!s1.isempty()) 
       cout<<s1.pop()<<" "; 
      cout<<endl; 
      cout<<"The elements in stack s2 are :\n"; 
      while(!s2.isempty()) 
       cout<<s2.pop()<<" "; 
      cout<<endl; 
      exit(1); 
     } 
    } 
    return 0; 
} 

Answer 1

不是一個調試器有用得多是仔細閱讀的藝術：

void init() 
{ 
    int top=0; 
} 

聲明本地變量top。

成員變量未初始化，導致未定義的行爲。
其中一個堆棧似乎工作只是運氣不好。

使其成爲一個正確分配：

void init() 
{ 
    top=0; 
} 

將做到這一點，但是這是C++，所以你應該使用構造函數：

class stack 
{ 
public: 
    stack(); 
// ... 
}; 

stack::stack() 
    : top(0) 
{ 

} 

然後

stack s1; 
stack s2; 
while(1) 
{ 
// ...