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我正在使用Spring數據JPA 1.4.3.RELEASE與Hibernate 4.2.7.Final 我能夠成功地創建一個基本存儲庫類， ： http://docs.spring.io/spring-data/jpa/docs/1.4.2.RELEASE/reference/html/repositories.html#repositories.custom-behaviour-for-all-repositories通用Spring數據JPA存儲庫實現按類類型加載數據
@NoRepositoryBean
public interface BaseRepository <T extends BaseEntity, ID extends Serializable>
extends JpaRepository<T, ID>
@NoRepositoryBean
public class BaseRepositoryImpl<T extends BaseEntity, ID extends Serializable>
extends SimpleJpaRepository<T, ID> implements BaseRepository<T, ID> {
我能夠與成功地工作：
public interface FlowerRepository extends BaseRepository<Flower, Long> {
現在，我試圖寫一個通用的實現（即擴展基礎資料庫）加載所有大參考喜歡花類型。 這是因爲我不想爲每個「類型」數據或「參考」數據建立一個存儲庫。 我想能夠管理，使用一個通用存儲庫通過傳遞一個特定的「類」類型（實現參考數據特定類型A接口）。對於EG
loadAll(FlowerType.class)
我用HBMS把Hibernate映射實體等等我有：
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://www.hibernate.org/dtd/hibernate-mapping-3.0.dtd">
<hibernate-mapping>
<class name="xxx.FlowerType" table="FLWTYP">
<meta attribute="extends" inherit="false">xxx.BaseReferenceType</meta>
<id name="primaryKey" type="string">
<column name="TYP_CDE" length="5" />
<generator class="assigned" />
</id>
public class FlowerType extends BaseReferenceType<String> implements ReferenceEntity<String>
public abstract class BaseReferenceEntity<T extends Serializable> extends BaseEntity implements
ReferenceEntity<T>
public abstract class BaseEntity implements DomainEntity
public interface ReferenceEntity<PK extends Serializable> {
持久性XML：
<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" version="2.0"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="xxxPU"
transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<shared-cache-mode>ENABLE_SELECTIVE</shared-cache-mode>
<properties>
<property name="hibernate.dialect" value="org.hibernate.dialect.Oracle10gDialect" />
<property name="hibernate.hbm2ddl.auto" value="none" />
<property name="hibernate.ejb.naming_strategy" value="org.hibernate.cfg.ImprovedNamingStrategy" />
<property name="hibernate.connection.charSet" value="UTF-8" />
<property name="hibernate.jdbc.batch_size" value="100" />
<property name="hibernate.show_sql" value="false" />
<property name="hibernate.format_sql" value="false" />
<property name="hibernate.transaction.flush_before_completion"
value="false" />
<property name="hibernate.connection.autocommit" value="false" />
<property name="hibernate.ejb.cfgfile" value="hibernate.cfg.xml"/>
<property name="jadira.usertype.autoRegisterUserTypes" value="true" />
<property name="jadira.usertype.databaseZone" value="jvm" />
<property name="jadira.usertype.javaZone" value="jvm" />
</properties>
</persistence-unit>
</persistence>
Hibernate的配置：
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-configuration PUBLIC "-//Hibernate/Hibernate Configuration DTD 3.0//EN"
"http://www.hibernate.org/dtd/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
<session-factory>
<mapping resource="FlowerType.hbm.xml"/>
<mapping resource="Flower.hbm.xml"/>
</session-factory>
</hibernate-configuration>
所以我看了一些教程等環節的職位，做了一些工作基礎上：
我：
@NoRepositoryBean
public interface CustomReferenceDataRepository<T extends BaseEntity & ReferenceEntity<PK>, PK extends Serializable> {
public Map<PK, T> findAll(Class<T> clz);
}
public interface ReferenceDataRepository extends BaseRepository, CustomReferenceDataRepository {
}
public class ReferenceDataRepositoryImpl<T extends BaseEntity & ReferenceEntity<PK>, PK extends Serializable>
implements CustomReferenceDataRepository<T, PK> {
@PersistenceContext
private EntityManager em;
@Override
public Map<PK, T> findAll(Class<T> clz) {
//do whatever
return null;
}
}
結束了一個例外：
Caused by: java.lang.IllegalArgumentException: Not an managed type: class xxx.BaseEntity
at org.hibernate.ejb.metamodel.MetamodelImpl.managedType(MetamodelImpl.java:200) ~[hibernate-entitymanager-4.2.7.Final.jar:4.2.7.Final]
at org.springframework.data.jpa.repository.support.JpaMetamodelEntityInformation.<init>(JpaMetamodelEntityInformation.java:68) ~[spring-data-jpa-1.4.3.RELEASE.jar:na]
at org.springframework.data.jpa.repository.support.JpaEntityInformationSupport.getMetadata(JpaEntityInformationSupport.java:65) ~[spring-data-jpa-1.4.3.RELEASE.jar:na]
at org.springframework.data.jpa.repository.support.JpaRepositoryFactory.getEntityInformation(JpaRepositoryFactory.java:146) ~[spring-data-jpa-1.4.3.RELEASE.jar:na]
我知道Hibernate不管理「BaseE ntity「，但我無法弄清楚我缺少的東西。
我是否需要爲參考數據實現通用資源庫甚至可能？ 如果是，我做錯了什麼？ 任何指導讚賞。 謝謝。
你可以粘貼你的JPA配置？已添加 –
。謝謝.. – souser