2017-07-19 76 views

回答

0

你所擁有的mysqli發送與查詢的連接。像這樣:

<?php 
$con=mysqli_connect("localhost","my_user","my_password","my_db"); 
// Check connection 
if (mysqli_connect_errno()) 
    { 
    echo "Failed to connect to MySQL: " . mysqli_connect_error(); 
    } 

// Perform queries 
mysqli_query($con,"SELECT * FROM Persons"); 
mysqli_query($con,"INSERT INTO Persons (FirstName,LastName,Age) 
VALUES ('Glenn','Quagmire',33)"); 

mysqli_close($con); 
?> 
+0

該網站的其他部分也被打破。例如:http://world2build.hol.es/Groups/它有一個標題。我已經使用代碼 –

+0

更改了我父親的登陸事件。是的,您必須查看錯誤並隨時查找使用mysqli_函數的所有地方並添加第二個參數。 – Von

+0

好吧生病開始這樣做。 –