2013-07-02 42 views

回答

2

使用列表理解:

>>> x = [[(u'reads_2.fq',), (u'reads_2.fq',), (u'reads_2.fq',), (u'reads_2.fq',), (u'reads_2.fq',)]] 
>>> [y[0] for y in x[0]] 
[u'reads_2.fq', u'reads_2.fq', u'reads_2.fq', u'reads_2.fq', u'reads_2.fq'] 

如果內的元組包含然後使用多個項目itertools.chain.from_iterable

>>> from itertools import chain 
>>> list(chain.from_iterable(x[0])) 
[u'reads_2.fq', u'reads_2.fq', u'reads_2.fq', u'reads_2.fq', u'reads_2.fq'] 
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