cakephp選擇多個只傳遞第一個值

Question

我已經生成了一個表單，多個字段是多個選擇。的值是從一個foreach產生（由於所需的格式）：

echo '<select name="data[formdata]['.$question['PrPageQuestion']['ID'].']" id="formdata'.$question['PrPageQuestion']['ID'].'" multiple="multiple">'; 
foreach($contacts as $contact): 
    echo '<option value="'.$contact['PrDataContact']['ID'].'">'.$contact['PrDataContact']['Name'].' ('.$contact['PrDataContact']['Email'].')</option>'; 
endforeach; 
echo '</select>'; 

然而，當我選擇多個並提交表單，我運行調試只有一個值被傳遞，而不是如預期字符串。

的HTML輸出是：

<select name="data[formdata][2]" id="formdata2" multiple="multiple"> 
    <option value="13">A Contact (a.contact@email.com)</option> 
    <option value="14">A. Nother-Contact (a.n.contact@email.com)</option> 
    <option value="15">A. New. Contact (anc@email.com)</option> 
    <option value="17">New Conti (new@conti.com)</option> 
</select> 

的var_dump的輸出是：

array(2) { 
    ["_method"]=> string(4) 
    "POST" ["data"]=> array(1) { 
     ["formdata"]=> array(8) { 
     //other data was here 
     [1]=> string(1) "1" 
     [2]=> string(2) "15" 
     [3]=> string(1) "4" 
     [4]=> string(0) "" 
     } 
    } 
} 

Answer 1

您需要在名稱後加[]告訴HTML，這是值的數組是提交

echo '<select name="data[formdata]['.$question['PrPageQuestion']['ID'].'][]" id="formdata'.$question['PrPageQuestion']['ID'].'" multiple="multiple">'; 
foreach($contacts as $contact): 
    echo '<option value="'.$contact['PrDataContact']['ID'].'">'.$contact['PrDataContact'['Name'].' ('.$contact['PrDataContact']['Email'].')</option>'; 
endforeach; 
echo '</select>'; 

您應該然後得到：

array(2) { 
    ["_method"]=> string(4) 
    "POST" ["data"]=> array(1) { 
     ["formdata"]=> array(8) { 
     //other data was here 
     [1]=> string(1) "1" 
     [2]=> array(2) { 
      [0]=>string(2) "15" 
      [1]=>string(2) "17" 
     }, 
     [3]=> string(1) "4" 
     [4]=> string(0) "" 
     } 
    } 
}