要檢索的SQLite

Question

代碼BLOB圖像保存圖像：

NSData *imageData=UIImagePNGRepresentation(animalImage); 
     NSString *insertSQL=[NSString stringWithFormat:@"insert into AnimalsTable (name,propertyID,animalID,breed,mainBreed,dateofbirth,sex,notes,imageData) values(\"%@\",\"%@\",\"%@\",\"%@\",\"%@\",\"%@\",\"%@\",\"%@\",\"%@\")",nameString,propertyString,animalidString,breedString,mainBreedString,dateString,sexString,notesString,imageData]; 
    sqlite3_stmt *addStatement; 
     NSLog(@"%@",appDelegate.sqlFile); 
    const char *insert_stmt=[insertSQL UTF8String]; 
    if (sqlite3_open([appDelegate.sqlFile UTF8String],&database)==SQLITE_OK) { 
     sqlite3_prepare_v2(database,insert_stmt,-1,&addStatement,NULL); 

     if (sqlite3_step(addStatement)==SQLITE_DONE) { 

      sqlite3_bind_blob(addStatement, 1, [imageData bytes], [imageData length], SQLITE_TRANSIENT); 
      NSLog(@"Data saved"); 

     } 
     else{ 
      //NSAssert1(0, @"Error while updating. '%s'", sqlite3_errmsg(database)); 

      NSLog(@"Some Error occured"); 
    } 

    sqlite3_close(database); 

對於檢索圖像：

NSString *select_sql=[NSString stringWithFormat:@"select name,animalID,imageData from AnimalsTable where mainBreed='%@' AND breed='%@'",mainString,subString]; 
     const char *sql = [select_sql UTF8String]; 
     sqlite3_stmt *selectstmt; 
     if(sqlite3_prepare_v2(database, sql, -1, &selectstmt, NULL) == SQLITE_OK) { 

      while(sqlite3_step(selectstmt) == SQLITE_ROW) { 

      NSString *animalName = [NSString stringWithUTF8String:(char *)sqlite3_column_text(selectstmt, 0)]; 
      NSString *animalid=[NSString stringWithUTF8String:(char *)sqlite3_column_text(selectstmt, 1)]; 
      NSData *dataForCachedImage = [[NSData alloc] initWithBytes:sqlite3_column_blob(selectstmt, 2) length: sqlite3_column_bytes(selectstmt, 2)];   
      [animalNamesArray addObject:animalName]; 
      [animalIDArray addObject:animalid]; 
      [imageDataArray addObject:dataForCachedImage]; 

     } 
    } 
} 
else 
    sqlite3_close(database); 

在UITableView的CellForIndexPath：

NSData *dataForCachedImage=[imageDataArray objectAtIndex:indexPath.row]; 
    UIImage *dataImage=[[UIImage alloc] init]; 
    dataImage=[UIImage imageWithData:dataForCachedImage]; 
    cell.imageView.image=dataImage; 

當我調試的代碼：

我得到字節對於NSData = 226381字節和對於dataImage 0x0。

請幫幫我。

Answer 1

您需要將您的值正確綁定到查詢才能正常工作。當您在第一行設置查詢時，將插入數據的描述，而不是正確的數據。如果您要記錄查詢，您可能會看到類似<0FFAEC32 ... 23F0E8D1>的內容。 然後您試圖稍後正確地綁定blob，但由於您的查詢寫入不正確，所以它沒有任何效果。

//Although you try to bind a blob here it does not get bound 
//to anything since you do not include a parameter template. 
sqlite3_bind_blob(addStatement, 1, [imageData bytes], [imageData length], SQLITE_TRANSIENT); 

要在這裏解決，這是一個小例子：

//query does not need to be an NSString* but just a const char * 
//replace all %@ with ? 
const char *sql = "INSERT INTO AnimalsTable(name, ..., imageData) values(?, ..., ?)"; 
if (sqlite3_open([appDelegate.sqlFile UTF8String],&database)==SQLITE_OK) { 
     sqlite3_prepare_v2(database,insert_stmt,-1,&addStatement,NULL); 

     //Bind all of the values here before you execute the statement 
     sqlite3_bind_text(addStatement, 1, [nameString UTF8String], -1, NULL); 
     ... 
     sqlite3_bind_blob(addStatement, 9, [imageData bytes], [imageData length], SQLITE_TRANSIENT); 

     if (sqlite3_step(addStatement)==SQLITE_DONE) { 
      NSLog(@"Data saved"); 
     } 
     ... 

     //You must finalize your statement before closing the database 
     sqlite3_finalize(addStatement); 
     sqlite3_close(database); 

使用綁定值有助於防止插入這可能是一個SQL注入攻擊，並提高對於經常運行的查詢的查詢性能數據無效。

注意*：如果你要做大量的SQL考慮使用FMDB甚至核心數據。