JOptionPane，返回幫助

Question

這是我在這個網站上的第一篇文章，因爲這個網站有很多幫助。我提出的不是一個問題，而是我想學習如何去做的事情。這裏是我的代碼

String a = JOptionPane.showInputDialog(null,"Please pick something for me to do master:\nMynumber,Read2me, Conversions"); 
if (a.equals("Mynumber")) 
{ 
    MyNumber = Integer.parseInt(JOptionPane.showInputDialog(null, "Please enter your number: ")); 
    String b = JOptionPane.showInputDialog(null,"Was Your number "+MyNumber+"\n Y/N"); 
    if (b.equals("y")) 
    { 
     JOptionPane.showMessageDialog(null,"Good...good, now lets play with\n your number"); 
    } 
    else if(b.equals("N")) 
    { 
     JOptionPane.showMessageDialog(null,"returning"); 

我的目標是當它到達最後的（當用戶鍵入n）的我想它返回到起始字符串，或字符串A，我將如何實現這個我代碼

Answer 1

添加一個循環，你的代碼，例如

while(true) { // instead of while(true) you can also write other condition 
String a = JOptionPane.showInputDialog(null,"Please pick something for me to do master:\nMynumber,Read2me, Conversions"); 
if (a.equals("Mynumber")) { 
    MyNumber = Integer.parseInt(JOptionPane.showInputDialog(null, "Please enter your number: ")); 
    String b = JOptionPane.showInputDialog(null,"Was Your number "+MyNumber+"\n Y/N"); 
    if (b.equals("y")) { 
     JOptionPane.showMessageDialog(null,"Good...good, now lets play with\n your number"); 
    } 
    else if(b.equals("N")) { 
     JOptionPane.showMessageDialog(null,"returning"); 
    } 
} 
}