我在論壇中搜索了任何幫助我,沒有任何工作的東西......我試圖在Phonegap上使用AJAX調用登錄PHP文件一個遠程服務器,但PHP文件不返回任何東西......我後我的代碼:通過Phonegap,AJAX,PHP和mySQL登錄不起作用
的AJAX調用:
$.ajax({
type: "POST",
data: 'userMail='+user+'&userPassword='+password,
dataType : 'html',
url : "http://www.eega.nl/app/login.php",
crossDomain: true,
async: false,
success: function(data){
if(data!='error'){
window.localStorage["userId"] = data;
location.href = "schedule.html";
}else{
alert("failed login");
location.href = "index.html";
}
},
error: function(){
alert("error");
window.open('schedule.html');
}
});
的PHP文件:
<?php
include 'connect.php';
header('Access-Control-Allow-Origin:*');
header('Access-Control-Allow-Methods: GET, PUT, POST, DELETE, OPTIONS, REQUEST');
header('Content-Type: application/json; charset=utf-8');
header('Access-Control-Max-Age: 3628800');
$data = array();
$userMail = $_POST["userMail"];
$userPassword = $_POST["userPassword"];
$cryptpass = md5($userPassword);
$sql = "SELECT tr_adr_id FROM elo_users WHERE email = '" . $userMail . "' AND crypt = '" . $cryptpass . "'";
//mysql_real_escape_string($userMail),
//mysql_real_escape_string($cryptpass));
$result = mysqli_query($sql);
//if($data = mysql_fetch_array($result)){
while($row = mysqli_fetch_array($result)) {
$data = $row['tr_adr_id'];
}
echo $data["tr_adr_id"];
mysqli_free_result($data);
mysqli_close();
?>
我試圖做的使用POST和GET的AJAX調用並在$ _POST,$ _GET和$ _REQUEST的PHP文件,沒有任何工作對我來說...
謝謝你提前!我仍在努力,試圖弄清楚什麼是錯誤的,我的代碼...
編輯:
中的index.html:
<!DOCTYPE HTML>
<html>
<head>
<meta name="viewport" content="width=320" user-scalable="no" />
<meta http-equiv="Content-type" content="text/html; charset=utf-8">
<link rel="stylesheet" href="css/bootstrap.min.css">
<link rel="stylesheet" href="css/bootstrap-theme.min.css">
<link rel="stylesheet" href="css/docs.min.css">
<link rel="stylesheet" href="css/jquery.mobile-1.4.3.min.css">
<link rel="stylesheet" href="css/general.css">
<script type="text/javascript" src="js/jquery-1.11.1.min.js"></script>
<script src="js/bootstrap.min.js"></script>
<script src="js/functions.js"></script>
<title>EegaApp</title>
<script type="text/javascript" charset="utf-8" src="cordova.js"></script>
</head>
<body>
<script type="text/javascript" src="js/jquery.mobile-1.4.3.min.js"></script>
<div id="eegaLogo">
<img class="bottom" src="images/eega_logo_loading.jpg"/>
<img class="top" src="images/eega_logo.jpg"/>
</div>
<a href="http://www.eega.nl/" data-mini="true" style="color:red; position: absolute; margin-left:35%; margin-top:43.5%; text-decoration:none;">www.eega.nl</a>
<!--*********Login form********-->
<form id="loginForm" class="form-signin" role="form" style="width:50%; text-align: center; margin-top: 55%; margin-left: 25%;" method="post">
<input id="userMail" name="userMail" class="form-control" type="email" autofocus="" required="" placeholder="Email"></input>
<input id="userPassword" name="userPassword" class="form-control" type="password" required="" placeholder="Password"></input>
<div>
<input type="checkbox" name="checkbox-0" id="checkbox-mini-0" class="custom" data-mini="true" />
<label for="checkbox-mini-0">Remember me</label>
</div>
<button type="submit" data-mini="true" onClick="login()">Login</button>
</form>
<!--*********End form*********-->
<!--THIS LINE IS JUST FOR TEST-->
<a href="schedule.html">schedule</a>
<!--*********Footer*********-->
<div id="footer">
<script>
function openExternal(elem) {
window.open(elem.href, "_system");
return false; // Prevent execution of the default onClick handler
}
</script>
<a class="col-xs-4" href="http://9292.nl/#" target="_blank" onClick="javascript:return openExternal(this)"><img id="footer-icon" src="images/9292_icon.jpg" style="width: 60px; height: 60px;"/></a>
<a class="col-xs-4" ><img id="footer-icon" src="images/maps_icon.jpg" style="width: 60px; height: 60px;"/></a>
<a class="col-xs-4" ><img id="footer-icon" src="images/call_icon2.jpg" style="width: 60px; height: 60px;"/></a>
</div>
<!--********End footer*********-->
</body>
使用'的var_dump($數據[ 「tr_adr_id」])'看看是否有變量..因爲我認爲有一個問題..你已經得到了子元素'$ data = $ row ['tr_adr_id'];'然後再次在'echo $ data [ 「tr_adr_id」];'..我想你應該只是'echo $ data;' – 2014-08-27 13:25:39
好!謝謝,我現在要試試這個! – 2014-08-27 13:27:09
你的phonegap index.html頁面是什麼樣子的? – 2014-08-27 13:28:22