-1
我正在與AJAX發送HTML FORM數據到PHP腳本,我將數據轉換爲關聯數組像這樣:訪問表單數據形式JSON對象轉換爲關聯數組中PHP
$ JSON = json_decode( $請求 - >獲取( 'JSON'),TRUE);
所以,當我傾倒可變我得到這個數組:
array(11) {
[0]=>
array(2) {
["name"]=>
string(21) "form[pickupDate][day]"
["value"]=>
string(1) "4"
}
[1]=>
array(2) {
["name"]=>
string(23) "form[pickupDate][month]"
["value"]=>
string(1) "1"
}
[2]=>
array(2) {
["name"]=>
string(22) "form[pickupDate][year]"
["value"]=>
string(4) "2016"
}
[3]=>
array(2) {
["name"]=>
string(22) "form[pickupTime][hour]"
["value"]=>
string(1) "0"
}
[4]=>
array(2) {
["name"]=>
string(21) "form[returnDate][day]"
["value"]=>
string(1) "1"
}
[5]=>
array(2) {
["name"]=>
string(23) "form[returnDate][month]"
["value"]=>
string(1) "1"
}
[6]=>
array(2) {
["name"]=>
string(22) "form[returnDate][year]"
["value"]=>
string(4) "2016"
}
[7]=>
array(2) {
["name"]=>
string(22) "form[returnTime][hour]"
["value"]=>
string(1) "0"
}
[8]=>
array(2) {
["name"]=>
string(19) "form[pickupAddress]"
["value"]=>
string(0) ""
}
[9]=>
array(2) {
["name"]=>
string(12) "form[agency]"
["value"]=>
string(1) "1"
}
[10]=>
array(2) {
["name"]=>
string(12) "form[_token]"
["value"]=>
string(43) "9dh6ghpMv5K9LUdSLvh6y2NOzqTzUrOfVriL8C63Ybs"
}
}
?我怎樣才能形式的[pickupDate] [日]無環路的價值?
使用$ json [0] ['value']。考慮json fromat不會改變。 –
可能的重複[如何從JSON提取數據與PHP?](http://stackoverflow.com/questions/29308898/how-do-i-extract-data-from-json-with-php) – miken32