MvvmLight打印消息調試

Question

是否有一個簡單的方法來打印所有Messenger.Default.Send（）來調試？不想覆蓋它們。

Answer 1

是的，所以我結束了與自己的包裝周圍信使。沒有聰明的解決方案，只是簡單的包裝。如果有其他人需要它：

public static class MvvmLightMessenger 
{ 
    public static void Register<TMessage>(object recipient, Action<TMessage> action) 
    { 
     Messenger.Default.Register(recipient,action); 
    } 

    public static void Register<TMessage>(object recipient, bool receiveDerivedMessagesToo, Action<TMessage> action) 
    { 
     Messenger.Default.Register(recipient, receiveDerivedMessagesToo, action); 
    } 

    public static void Register<TMessage>(object recipient, object token, Action<TMessage> action) 
    { 
     Messenger.Default.Register(recipient, token, action); 
    } 

    public static void Register<TMessage>(object recipient, object token, bool receiveDerivedMessagesToo, Action<TMessage> action) 
    { 
     Messenger.Default.Register(recipient, token, receiveDerivedMessagesToo, action); 
    } 





    public static void Send<TMessage>(TMessage message) 
    { 
     Debug.WriteLine("{!} Message: " + message); 
     Messenger.Default.Send<TMessage>(message); 
    } 

    public static void Send<TMessage, TTarget>(TMessage message) 
    { 
     Debug.WriteLine("{!} Message: " + message + " to target: " + typeof(TTarget)); 
     Messenger.Default.Send<TMessage, TTarget>(message); 
    } 

    public static void Send<TMessage>(TMessage message, object token) 
    { 
     Debug.WriteLine("{!} Message: " + message + " token: " + token); 
     Messenger.Default.Send<TMessage>(message, token); 
    } 







    public static void Unregister<TMessage>(object recipient) 
    { 
     Messenger.Default.Unregister<TMessage>(recipient); 
    } 

    public static void Unregister<TMessage>(object recipient, Action<TMessage> action) 
    { 
     Messenger.Default.Unregister<TMessage>(recipient, action); 
    } 

    public static void Unregister<TMessage>(object recipient, object token) 
    { 
     Messenger.Default.Unregister<TMessage>(recipient, token); 
    } 

    public static void Unregister<TMessage>(object recipient, object token, Action<TMessage> action) 
    { 
     Messenger.Default.Unregister<TMessage>(recipient, token, action); 
    } 
} 

Answer 2

在抽象的ViewModel中創建一個每個人都從中繼承的函數，該函數使用一個定義或全局變量來確定它是否也被調試。如果您正在以調試或發佈的方式運行，這也可能是。

public abstract BaseViewModel 
    public SendMessage() 
    { 
     if(DEBUG) // The global variable, or definition, or current run type - whatever 
      Debug.WriteLine(); 
     // else // Commented if you want to always send, uncomment if you want to send instead. 
     Messenger.Default.Send(); 
    } 


public RealViewModel : BaseViewModel 
... 
    SomeMethod() 
    { 
     ... 
     base.SendMessage();