我試圖創建一個CRUD儀表板,使用MySql後端和引導前端用PHP和PDO與數據庫進行通信。我是網頁開發的一個小老頭,但不是編碼。使用PHP,PDO和MySql顯示在一個頁面上的兩個表格
目標是創建一個Web應用程序來記錄我的患者諮詢。因此,我的表結構是一個單獨的「主」表和兩個與「主」表關聯的子表,名爲「諮詢」和「過程」。
我想做一個儀表板,在那裏顯示我的「主」表,然後在它下面添加兩個子表。 (稍後我會更好地設計風格,但我試圖讓它工作)。
以下是我能想到的最好的MWE(如果有人有一個更簡單的解決方案,會喜歡它)。第一個「日誌病人」表運作良好,並能很好地顯示病人行。它的第二個表是問題,特別是:
$sql = "SELECT * FROM proc";
if($result = $pdo->query($sql)){
if($result->rowCount() > 0){
這是我不斷收到錯誤的區域。錯誤是:
Fatal error: Uncaught Error: Call to a member function query() on null in /home/paincl5/public_html/logbook/logbook.php:110 Stack trace: #0 {main} thrown in /home/paincl5/public_html/logbook/logbook.php on line 110
在管線110中的代碼是
unset($pdo);
我完整的代碼:
<div class="wrapper">
<div class="container-fluid">
<div class="row">
<div class="col-md-12">
<div class="page-header clearfix">
<h2 class="pull-left">Logbook Patients</h2>
<a href="create.php" class="btn btn-success pull-right" >Add New Patient</a>
</div>
<?php
// Include config file
require_once 'config.php';
// Attempt select query execution
$sql = "SELECT * FROM main";
if($result = $pdo->query($sql)){
if($result->rowCount() > 0){
echo "<div style='height:300px;overflow-y:scroll;;'>";
echo "<table class='table table-bordered table-striped'>";
echo "<thead>";
echo "<tr>";
echo "<th>Surname</th>";
echo "<th>first_name</th>";
echo "<th>DOB</th>";
echo "<th>Hospital</th>";
echo "<th>MRN</th>";
echo "<th>Action</th>";
echo "</tr>";
echo "</thead>";
echo "<tbody>";
while($row = $result->fetch()){
echo "<tr>";
echo "<td>" . $row['Surname'] . "</td>";
echo "<td>" . $row['first_name'] . "</td>";
echo "<td>" . $row['DOB'] . "</td>";
echo "<td>" . $row['Hospital'] . "</td>";
echo "<td>" . $row['MRN'] . "</td>";
echo "<td>";
echo "<a href='read.php?id=". $row['id'] ."' title='View Record' data-toggle='tooltip'><span class='glyphicon glyphicon-eye-open'></span></a>";
echo "<a href='update.php?id=". $row['id'] ."' title='Update Record' data-toggle='tooltip'><span class='glyphicon glyphicon-pencil'></span></a>";
echo "<a href='delete.php?id=". $row['id'] ."' title='Delete Record' data-toggle='tooltip'><span class='glyphicon glyphicon-trash'></span></a>";
echo "</td>";
echo "</tr>";
}
echo "</tbody>";
echo "</table>";
echo "</div>";
// Free result set
unset($result);
} else{
echo "<p class='lead'><em>No records were found.</em></p>";
}
} else{
echo "ERROR: Could not able to execute $sql. " . $mysqli->error;
}
// Close connection
unset($pdo);
?>
</div>
</div>
</div>
</div>
// Procedure Table
<div class="wrapper">
<div class="container-fluid">
<div class="row">
<div class="col-md-12">
<div class="page-header clearfix">
<h2 class="pull-left">Procedures</h2>
<a href="create_proc.php" class="btn btn-success pull-right" >Add New Procedure</a>
</div>
<?php
// Include config file
require_once 'config.php';
// Attempt select query execution
$sql = "SELECT * FROM proc";
if($result = $pdo->query($sql)){
if($result->rowCount() > 0){
echo "<div style='height:300px;overflow-y:scroll;;'>";
echo "<table class='table table-bordered table-striped'>";
echo "<thead>";
echo "<tr>";
echo "<th>Procedure Type</th>";
echo "<th>Procedure Name</th>";
echo "<th>Notes</th>";
echo "<th>Action</th>";
echo "</tr>";
echo "</thead>";
echo "<tbody>";
while($row = $result->fetch()){
echo "<tr>";
echo "<td>" . $row['procedure_type'] . "</td>";
echo "<td>" . $row['procedure_name'] . "</td>";
echo "<td>" . $row['notes'] . "</td>";
echo "<td>";
echo "<a href='update.php?id=". $row['id1'] ."' title='Update Record' data-toggle='modal' data-target='#myModal' ><span class='glyphicon glyphicon-pencil'></span></a>";
echo "<a href='delete.php?id=". $row['id1'] ."' title='Delete Record' data-toggle='tooltip'><span class='glyphicon glyphicon-trash'></span></a>";
echo "</td>";
echo "</tr>";
}
echo "</tbody>";
echo "</table>";
echo "</div>";
// Free result set
unset($result);
} else{
echo "<p class='lead'><em>No records were found.</em></p>";
}
} else{
echo "ERROR: Could not able to execute $sql. " . $mysqli->error;
}
// Close connection
unset($pdo); //Here occurs the error (line 110)
?>
</div>
</div>
</div>
</div>
完美的是,我只在第三個表中留下了未設置的引用(未在上面顯示),並修復了它。優秀。 – user2444133