我不明白爲什麼string.size返回它所做的

Question

long_string = <<EOS 
It was the best of times, 
It was the worst of times. 
EOS 

返回53.爲什麼？空白的數量？即使如此。我們如何得到53？

這個怎麼樣？

 def test_flexible_quotes_can_handle_multiple_lines 
    long_string = %{ 
It was the best of times, 
It was the worst of times. 
} 
    assert_equal 54, long_string.size 
    end 

    def test_here_documents_can_also_handle_multiple_lines 
    long_string = <<EOS 
It was the best of times, 
It was the worst of times. 
EOS 
    assert_equal 53, long_string.size 
    end 

是這種情況，因爲％{情況下，可計算每個/n爲一個字符，被認爲是一個第一行之前，一個在端孤單，然後在第2行的末尾，而在EOS這種情況在第一行之前只有一個，第一行之後有一個？換句話說，爲什麼前者54和後者53？

Answer 1

爲：

long_string = <<EOS 
It was the best of times, 
It was the worst of times. 
EOS 

String is: 
"It was the best of times,\nIt was the worst of times.\n" 

It was the best of times, => 25 
<newline> => 1 
It was the worst of times. => 26 
<newline> => 1 
Total = 25 + 1 + 26 + 1 = 53 

而且

long_string = %{ 
It was the best of times, 
It was the worst of times. 
} 

String is: 
"\nIt was the best of times,\nIt was the worst of times.\n" 
#Note leading "\n" 

工作原理：

在<<EOS的情況下，它後面的線是字符串的一部分。 <<與<<相同，並且在行末尾的所有文本將成爲確定字符串何時結束的「標記」的一部分（在這種情況下，行上的EOS本身與<<EOS匹配）。

在%{...}的情況下，它只是一個不同的分隔符代替"..."。所以當你在%{之後的新行開始時，該換行符就是字符串的一部分。

試試這個例子，你會看到%{...}如何爲"..."工作一樣：

a = " 
It was the best of times, 
It was the worst of times. 
" 
a.length # => 54 

b = "It was the best of times, 
It was the worst of times. 
" 
b.length # => 53