如何從PHP中的MySQL時間戳計數打印月份名稱？

Question

我使用json輸出計算按時間戳月份的文章視圖。我有這樣的代碼：

$value = array(); 
$stats = Access::FETCH("SELECT COUNT(*) AS id FROM news_stats GROUP BY YEAR(date), MONTH(date)"); 

foreach($stats as $key => $value){ 

    $rows2[] = $value['id']; 

    } 
echo json_encode($rows2); 

輸出爲：NOTE: this is count for month each month

["1","6"] 

我需要爲這個輸出中類似這樣的打印月份名稱：

["january","June"] 

如何在打印月份名嗎？ Menaig是：1 , 6從哪月算起？

Answer 1

試試這個：

$value = array(); 
$stats = Access::FETCH("SELECT id, YEAR(FROM_UNIXTIME(date)) AS `YEAR`, 
       MONTHNAME(FROM_UNIXTIME(date)) AS `MONTH`, 
       COUNT(*) AS id 
     FROM news_stats GROUP BY `YEAR`, `MONTH` ORDER BY `YEAR` DESC, `MONTH`"); 


foreach($stats as $key => $value){ 

    $rows2[] = $value['MONTH']; 

    } 
    echo json_encode($rows2); 

輸出是：

["June","August"] 

享受！

Answer 2

您可以在foreach循環中使用類似的代碼如下：

<?php 
$monthNum = $value['id']; 
$monthName = date("F", mktime(0, 0, 0, $monthNum, 10)); 
?> 

從接過：http://gilbert.pellegrom.me/php-month-number-to-month-name-the-easy-way/

Answer 3

你可以做到這一點在MySQL本身通過調整你的查詢，像這樣使用MONTHNAME：

SELECT COUNT(*) AS id FROM news_stats GROUP BY YEAR(date), MONTHNAME(date); 

在PHP中通過mktime/date組合的唯一實際價值是你的s cript需要數字值以及整個月份名稱本身。但是，MySQL也可以通過類似SELECT YEAR(date) as year, MONTH(date) as month, MONTHNAME(date) as month_name…的方式來解決這個問題，但這完全取決於編碼需求。

此外，剛剛意識到它在您的示例中全部編碼爲GROUP BY。所以，這可能會更好地工作：

SELECT COUNT(*) AS id, 
YEAR(date) as `year`, 
MONTH(date) as `month`, 
MONTHNAME(date) as `month_name`, 
FROM `news_stats` 
GROUP BY `year`, `month`;