我怎麼能得到搜索結果與分頁工作？

Question

喜的朋友，所以我得到了它有選項要麼選擇一個值或選擇該搜索條件的所有東西，但任何方式這裏的問題是我不知道如何得到的結果保持不變，當分頁發生？

截至目前，如果點擊下一頁或任何頁面，它將顯示空白頁面，因爲除了頁碼之外沒有任何內容被傳遞。

這裏是我的代碼

<?php 

    $title = clean($_REQUEST['title']); 
    $name = clean($_REQUEST['name']); 
    $description = clean($_REQUEST['description']); 

    $criteria = array(); 

      if($title !='') 
      { 
       $criteria[] = "title = '".$title."'"; 
      }elseif($title =='All') 
       criteria[] = "title = ''"; 
      } 

      if($name !='') 
      { 
       $criteria[] = "name = '".$name."'"; 
      }elseif($name =='All') 
       criteria[] = "name = ''"; 
      } 

      if($description !='') 
      { 
       $criteria[] = "description = '".$description."'"; 
      }elseif($description =='All') 
       criteria[] = "description = ''"; 
    } 

    try { 

    $total = $db->query('SELECT COUNT(*) FROM table WHERE '.implode(' AND ', $criteria).'')->fetchColumn(); 
    global $per_page; 

    $pages = ceil($total/$per_page); 

    $page = min($pages, filter_input(INPUT_GET, 'page', FILTER_VALIDATE_INT, array(
     'options' => array(
      'default' => 1, 
      'min_range' => 1, 
     ), 
    ))); 


    $offset = ($page - 1) * $per_page; 
    $start = $offset + 1; 
    $end = min(($offset + $per_page), $total); 


    $stmt = $db->prepare('SELECT * FROM table WHERE '.implode(' AND ', $criteria).' ORDER BY id DESC LIMIT :per_page OFFSET :offset'); 

    $stmt->bindParam(':per_page', $per_page, PDO::PARAM_INT); 
    $stmt->bindParam(':offset', $offset, PDO::PARAM_INT); 
    $stmt->execute(); 

    if ($stmt->rowCount() > 0) { 
     $stmt->setFetchMode(PDO::FETCH_ASSOC); 
     $iterator = new IteratorIterator($stmt); 
     foreach ($iterator as $row) {   

       echo $row['id']; 
     } 

    echo '<div id="pagination"> 
    <div id="pagiCount">'; 
     $prevlink = ($page > 1) ? '<span id="prev"><a href="?page=1" title="First page">First</a></span> <span id="prev"><a href="?page=' . ($page - 1) . '" title="Previous page"><<</a></span>' : ''; 
     $nextlink = ($page < $pages) ? '<span id="next"><a href="?page=' . ($page + 1) . '" title="Next page">>></a></span> <span id="next"><a href="?page=' . $pages . '" title="Last page">Last</a></span>' : ''; 
     echo '<div id="paging"><p><small>', $prevlink, ' Page ', $page, ' of ', $pages, '', $nextlink, '</small></p></div>';   
    echo '</div></div>'; 
    } else { 
     echo '<p>Nothing found.</p>'; 
    } 
} catch (Exception $e) { 
    echo '<p>Nothing found.</p>'; 
} 
?> 

我真的會很感激你爲你用這種幫助。歡呼聲

Answer 1

你必須regenarate查詢字符串都只用一個頁面相同的參數。

所以我認爲這樣的事情會工作：

//regenerate query string with new page 
$cur_params = $_GET; 
unset($cur_params["page"]); 
$cur_url = strtok($_SERVER["REQUEST_URI"],"?") . "?" . http_build_query($cur_params, "", "&"); 
$page_back_url = $cur_url . (empty($cur_params) ? "" : "&") . "page=" . ($page - 1); 
$page_next_url = $cur_url . (empty($cur_params) ? "" : "&") . "page=" . ($page + 1); 
$page_last_url = $cur_url . (empty($cur_params) ? "" : "&") . "page=$pages";