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我正在使用spring-data-jpa + hibernate。 1.I碰上以下例外 ......「java.lang.IllegalArgumentException：具有該位置[1]的參數不存在」當我使用spring-data-jpa
Caused by: java.lang.IllegalArgumentException: Parameter with that position [1] did not exist
at org.hibernate.jpa.spi.BaseQueryImpl.findParameterRegistration(BaseQueryImpl.java:518) ~[BaseQueryImpl.class:4.3.7.Final]
at org.hibernate.jpa.spi.BaseQueryImpl.setParameter(BaseQueryImpl.java:674) ~[BaseQueryImpl.class:4.3.7.Final]
at org.hibernate.jpa.spi.AbstractQueryImpl.setParameter(AbstractQueryImpl.java:198) ~[AbstractQueryImpl.class:4.3.7.Final]
at org.hibernate.jpa.spi.AbstractQueryImpl.setParameter(AbstractQueryImpl.java:49) ~[AbstractQueryImpl.class:4.3.7.Final]
at org.springframework.data.jpa.repository.query.ParameterBinder.bind(ParameterBinder.java:165) ~[ParameterBinder.class:?]
at org.springframework.data.jpa.repository.query.StringQueryParameterBinder.bind(StringQueryParameterBinder.java:66) ~[StringQueryParameterBinder.class:?]
......
相信異常來自
public interface FamousExperienceDao extends PagingAndSortingRepository<FamousExperience,
Long>,JpaSpecificationExecutor<FamousExperience>
{
@Query(value =
"select new com.tujia.community.entity.BriefInfomation(f.id,f.title,f.summary,f.thumbnail,f.author, f.issueDate, f.counter) from FamousExperience f"
,countQuery ="select count(f.id) from FamousExperience f")
public Page<BriefInfomation> findExps(Specification<FamousExperience> spec, Pageable pgbl);
}
，因爲我從PARAMS功能findExps的擺脫規格規格後，它工作得很好，我只想補充規範查詢。
BYW，FamousExperience擴展BriefInfomation。我使用JPA Query的「構造函數表達式」功能，當我嘗試查詢時，我不需要屬性「內容」。
@Entity
@Table(name = "famous_experience")
public class FamousExperience extends BriefInfomation
{
private String content;
/**
* @return the content
*/
public String getContent()
{
return content;
}
/**
* @param content the content to set
*/
public void setContent(String content)
{
this.content = content;
}
}
請幫幫我！