我試圖創建表達式,但失敗。如何手動構建將始終返回true的表達式?
我想建立類似Expression<Func<typeof(type), bool>> expression = _ => true;
我嘗試:
private static Expression GetTrueExpression(Type type)
{
LabelTarget returnTarget = Expression.Label(typeof(bool));
ParameterExpression parameter = Expression.Parameter(type, "x");
var resultExpression =
Expression.Return(returnTarget, Expression.Constant(true), typeof(bool));
var delegateType = typeof(Func<,>).MakeGenericType(type, typeof(bool));
return Expression.Lambda(delegateType, resultExpression, parameter); ;
}
用法:
var predicate = Expression.Lambda(GetTrueExpression(typeof(bool))).Compile();
但我得到的錯誤:Cannot jump to undefined label ''
您可以嘗試使用'PredicateBuilder'由阿爾巴哈利兄弟。 'var'expr = PredicateBuilder.True();'http://www.albahari.com/nutshell/predicatebuilder.aspx –
willaien
'typeof(type)'in your expression will * always * return'Type' – maksymiuk
This works too: '公共靜態表達式GetTrueExpression()=> Expression >)(x => true); var predicate = GetTrueExpression