我已經回答了我自己的問題,以幫助未來的觀衆。
使用維基百科上找到的顏色公式和註釋中顯示的顏色公式,該功能將採用3個參數並返回最接近的顏色。
const int distinctRGB[22][3] = {{255, 255, 255},{0,0,0},{128,0,0},{255,0,0},{255, 200, 220},{170, 110, 40},{255, 150, 0},{255, 215, 180},{128, 128, 0},{255, 235, 0},{255, 250, 200},{190, 255, 0},{0, 190, 0},{170, 255, 195},{0, 0, 128},{100, 255, 255},{0, 0, 128},{67, 133, 255},{130, 0, 150},{230, 190, 255},{255, 0, 255},{128, 128, 128}};
const String distinctColors[22] = {"white","black","maroon","red","pink","brown","orange","coral","olive","yellow","beige","lime","green","mint","teal","cyan","navy","blue","purple","lavender","magenta","grey"};
String closestColor(int r,int g,int b) {
String colorReturn = "NA";
int biggestDifference = 1000;
for (int i = 0; i < 22; i++) {
if (sqrt(pow(r - distinctRGB[i][0],2) + pow(g - distinctRGB[i][1],2) + pow(b - distinctRGB[i][2],2)) < biggestDifference) {
colorReturn = distinctColors[i];
biggestDifference = sqrt(pow(r - distinctRGB[i][0],2) + pow(g - distinctRGB[i][1],2) + pow(b - distinctRGB[i][2],2));
}
}
return colorReturn;
}
此功能,爲了做到式較少打字使用Math.h
。
https://en.wikipedia.org/wiki/Color_difference –
我不是專家,但也許採取差異的總和或差異的平方和的最接近的價值? – agbinfo
沒有確切的答案 - 嘗試創建一個感知均勻的色彩空間,讓您在深水中非常迅速。但是,紅色差異5倍,綠色差異9倍,藍色差異2倍是一個好的開始。 –