無法從iPhone應用程序獲取HTTP GET請求

我正在編寫一個示例PHP Web服務，它正在向iPhone發送GET Http請求到Web服務器。服務器端代碼返回JSON數據到iPhone，服務器端的代碼如下所示：無法從iPhone應用程序獲取HTTP GET請求

<?php 

function getUsers(){ 
    $con=mysql_connect("localhost","root","123456") or die(mysql_error()); 

     if(!mysql_select_db("eventsfast",$con)) 
    { 
     echo "Unable to connect to DB"; 
     exit; 
    } 

    $sql="SELECT * from users"; 
    $result=mysql_query($sql); 
    if(!$result) 
    { 
     die('Could not successfully run query Error:'.mysql_error()); 
    } 
    $data = array(); 

    while($row = mysql_fetch_assoc($result)){ 
    $data['username'][] = $row['username']; 
    $data['password'][]= $row['password']; 
    } 

    mysql_close($con); 
    //print_r(json_encode($data)); 
    //return (json_encode($data)); 
    return json_encode('success'); 
} 

getUsers(); 

?>

它是一個簡單的代碼，從用戶表中獲取的所有數據，並將其發送到iPhone應用程序。

電話應用程序

- (void)viewDidLoad { 
    [super viewDidLoad]; 
    responseData = [[NSMutableData data] retain]; 
    NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:@"http://localhost:8888/GetData.php"]]; 
    [[NSURLConnection alloc] initWithRequest:request delegate:self]; 
} 

- (void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response 
{ 
    [responseData setLength:0]; 
} 
- (void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data 
{ 
    [responseData appendData:data]; 
} 
- (void)connection:(NSURLConnection *)connection didFailWithError:(NSError *)error 
{ 
    label.text = [NSString stringWithFormat:@"Connection failed: %@", [error description]]; 
} 
- (void)connectionDidFinishLoading:(NSURLConnection *)connection 
{ 
    [connection release]; 

    NSString *responseString = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding]; 

    [responseData release]; 

    NSError *error; 
    SBJSON *json = [[SBJSON new] autorelease]; 
    NSArray *luckyNumbers = [json objectWithString:responseString error:&error]; 
    [responseString release]; 

    if (luckyNumbers == nil) 
     label.text = [NSString stringWithFormat:@"JSON parsing failed: %@", [error localizedDescription]]; 
    else { 
     NSMutableString *text = [NSMutableString stringWithString:@"Lucky numbers:\n"]; 

     for (int i = 0; i < [luckyNumbers count]; i++) 
      [text appendFormat:@"%@\n", [luckyNumbers objectAtIndex:i]]; 
     NSLog(text); 

     label.text = text; 
    } 
}

的問題

的問題是，什麼是對應用程序的iPhone那邊傳來。該響應不包含任何內容。

來源

2010-04-22 user317192

你能修正代碼清單1.固定間距，以便代碼格式正確，並且2.只包括與你的問題相關的班級部分？ – 2010-04-22 07:29:00

我認爲你的web服務需要你還沒有通過的USERID和PASSWORD。 – Tirth 2010-04-22 07:48:10

@ user3171192，我認爲會有問題是你不通過用戶ID和密碼的NSURLRequest到Web service.Therefore它可能也可以不給你連接的響應。請使用

在

-(void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data 
{ 
    [responseData appendData:data]; 
    NSLog(@"Response of web service %@", responseData); 
}

的部分您將獲得廣發行代碼的確切回覆。我希望你能解決你的問題。對不起英文。

來源

2010-04-22 07:43:22 Tirth

無法從iPhone應用程序獲取HTTP GET請求

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