0
我在<body>
結束標記之外編寫了JavaScript。 Firebug無法檢測到JavaScript,我無法檢測到JavaScript錯誤。爲什麼Firebug無法檢測到一些JavaScript?
這裏是我的代碼:
</body>
<script type="text/javascript">
function displayIFrameContent()
{
var iFrame = document.getElementById("link");
var if1= "<iframe src='http://leadmarket.hol.es/forms/solar-power.php?adv_id=" + <?php echo($fetch_users_data['id']); ?>;
var if2= "<iframe src='http://leadmarket.hol.es/forms/kitchen-installation.php?adv_id=" + <?php echo($fetch_users_data['id']); ?>;
var if3= "<iframe src='http://leadmarket.hol.es/forms/conservatory.php?adv_id=" + <?php echo($fetch_users_data['id']);; ?>;
var host = document.getElementById("host");
var subId = document.getElementById("subid");
var errorClass = "box form-validation-error border-width-2";
if(host.value == "")
changeClass("host", errorClass);
if(host.value != "")
{
var iFrameEnd = " width='280' height='330' frameborder='0' scrolling='no'></iframe>";
var leadTypeSelect = document.getElementById("leadType");
var leadTypeValue = leadTypeSelect.options[leadTypeSelect.selectedIndex].value;
iFrame.value = "";
if(leadTypeValue == 1)
iFrame.value = if1 + "&" + "sub_id=" + subId.value + "&source=" + host.value + "'" + iFrameEnd;
if(leadTypeValue == 2)
iFrame.value = if2 + "&" + "sub_id=" + subId.value + "&source=" + host.value + "'" + iFrameEnd;
if(leadTypeValue == 3)
iFrame.value = if3 + "&" + "sub_id=" + subId.value + "&source=" + host.value + "'" + iFrameEnd;
}
}
function changeClass(id, classname)
{
document.getElementById(id).setAttribute("class", classname);
}
</script>
</html>
您的幫助將不勝感激。提前致謝!
你關閉''的''