爲分頁

Question

我試圖做CakePHP的定製進行分頁設置的條件，事情是，我想通過自定義的條件，這樣的事情：

$conditions['People'] = $this->People->find('all', 
    array(
     'order' => array('People.id DESC'), 
     'limit' => 16, 
     'order' => 'People.id DESC' 
    ) 
); 

$people = $this->paginate('People',$conditions); 

這基本上是所有涉及分頁的代碼，但它它不會工作，它會引起它找不到列人...

我只想做自定義條件的分頁，也就是說，我想事先設置條件，有沒有辦法做那？

Answer 1

好吧，我解決了這個問題，這就是我所做的： 首先我聲明它可以是空的，如果你想：

public $paginate = array('People'=>array(
     'limit' => 6, 
     'order' => 'People.id DESC' 
    )); 

然後，只要我想改變一些東西，我只是做：

$this->paginate['People']['limit'] = 12; 

Answer 2

你看過文檔嗎？

據的文檔，你應該添加的條件是這樣的：

public function list_recipes() { 
    $this->Paginator->settings = array(
     'conditions' => array('Recipe.title LIKE' => 'a%'), 
     'limit' => 10 
    ); 
    $data = $this->Paginator->paginate('Recipe'); 
    $this->set(compact('data')); 
} 

因此猜測這應該工作：

public function list_people() { 
    $this->Paginator->settings = array('order' => array('People.id DESC'),'limit' => 16,'order' => 'People.id DESC'); 
    $data = $this->Paginator->paginate('People'); 
    $this->set(compact('data')); 
} 

Answer 3

這裏是我如何在蛋糕2.X做

首先是一定要包括在控制器中分頁程序組件和幫手，像

$public $components = array(
    'Paginator' 
); 

$public $helpers = array(
    'Paginator' 
); 

然後在動作

$options = array(
    'conditions' => array(
     'Post.status' => 1 
    ), 
    'fields' => array(
     'Post.id', 
     'Post.title', 
     'Post.created' 
    ), 
    'order' => array(
     'Post.created' => 'DESC' 
    ), 
    'limit' => 10 
); 

$this->Paginator->settings = $options; 
$posts = $this->Paginator->paginate('Post');