我正在學習java中的servlet。 Bellow是我的代碼,它假設獲取url的內容,將它存儲在數組列表中,並將其顯示在屏幕上。出於某種原因,我無法獲得字符串數組內容顯示在屏幕上。當我加載頁面時,我收到「不幸」的消息。任何想法爲什麼?感謝在(servlets)屏幕上打印字符串數組存儲的數據
//package fortune;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.net.URL;
import java.util.ArrayList;
import java.util.Random;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import static java.util.Arrays.*;
import java.util.Collections;
import java.util.List;
@WebServlet(name = "FortuneServlet", urlPatterns = {"/"})
public class FortuneServlet extends HttpServlet {
//private String [] cookies = null;
List<String> cookies = new ArrayList<>();
String line ;
public void geturl(String[] args) {
try
{
URL url = new URL(" http://fortunes.cat-v.org/openbsd/");
//URL url = new URL(" http://bbc.com");
// read text returned by server
BufferedReader in = new BufferedReader(new InputStreamReader(url.openStream()));
while((line = in.readLine()) != null)
{
cookies.add(line);
//line = in.readLine();
}
in.close();
}
catch (java.net.MalformedURLException e) {
System.out.println("Malformed URL: " + e.getMessage());
}
catch (IOException e) {
System.out.println("I/O Error: " + e.getMessage());
}
}
public void init() throws ServletException {
}
@Override
protected void doGet(
HttpServletRequest request,
HttpServletResponse response)
throws ServletException, IOException {
response.setCharacterEncoding("UTF-8");
response.setContentType("text/plain");
if (cookies != null)
{
//response.getWriter().println(
// cookies[new Random().nextInt(cookies.length)]
//);
for (String str: cookies)
{
Collections.shuffle(cookies);
response.getWriter().println(str);
}
}
else {
response.getWriter().println("No luck!");
}
}
}
您是否收到任何錯誤和異常?或者你得到了什麼輸出? –
不,我沒有得到任何錯誤!我得到一個空白屏幕 – zamzam