計數在查詢

專家多個列我有四個查詢：計數在查詢

查詢＃1：

select 
satisfaction_score,count(satisfaction_score) as Satisfaction_count 
from j_survey_response 
where satisfaction_score != 0 
group by satisfaction_score

的輸出將是

satisfaction_score Satisfaction_count 
4       329 
5       859

查詢＃2：

select 
response_score,count(response_score) as response_count 
from j_survey_response 
where response_score != 0 
group by response_score

OUTPUT

response_score response_count 
3     42 
5     980

查詢＃3：

select 
responder_score,count(responder_score) as responder_count 
from j_survey_response 
where responder_score != 0 
group by responder_score

OUTPUT

responder_score responder_count 
4     236 
5     987

查詢＃4：

select 
service_score,count(service_score) as service_count 
from j_survey_response 
where service_score != 0 
group by service_score

OUTPUT

service_score service_count 
5     966

但我需要的輸出如下

score satisfaction_count response_count responder_count service_count 
3   null     42   null    null 
4   329    null    236    null 
5   859     980    986    966

在此先感謝

來源

2016-02-17 Jeeva Balan

如果你喜歡，可以考慮下列行爲這個簡單的兩步過程：1 。如果您還沒有這樣做，請提供適當的DDL（和/或sqlfiddle），以便我們可以更輕鬆地複製問題。 2.如果您尚未這樣做，請提供與步驟1中提供的信息相對應的所需結果集。 – Strawberry

看起來與您之前的問題非常相似http://stackoverflow.com/questions/35431072/count-multiple -columns-in-one-queries –

與此類似，但如果僅返回此輸入中的第五列 –

試試這個：

select score, 
     max(if(score_type='satisfaction_score',count,null)) as satisfaction_count, 
     max(if(score_type='response_score',count,null)) as response_count, 
     max(if(score_type='responder_score',count,null)) as responder_count, 
     max(if(score_type='service_score',count,null)) as service_count 
from (
    select score,count(satisfaction_score) as count,'satisfaction_score' as score_type from j_survey_response where satisfaction_score != 0 group by satisfaction_score 
    union all 
    select score,count(response_score) ,'response_score' as score_type from j_survey_response where response_score != 0 group by response_score 
    union all 
    select score,count(responder_score) ,'responder_score' as score_type from j_survey_response where responder_score != 0 group by responder_score 
    union all 
    select score,count(service_score) ,'service_score' as score_type from j_survey_response where service_score != 0 group by service_score 
) as scores 
group by scores.score

來源

2016-02-17 10:55:31

回答

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