排除友誼頁面 - MySQL

Question

這是我的查詢來獲取用戶的朋友。但有一個問題。如果接收者是會話用戶，它將以朋友身份返回自己。

SELECT user.name_surname, user.id, friendship.receiver_id, friendship.sender_id 
FROM user 
JOIN friendship ON user.id = friendship.receiver_id 
WHERE 
    (friendship.receiver_id =".$_SESSION["SES_USER_ID"]." OR friendship.sender_id =".$_SESSION["SES_USER_ID"].") 
    AND is_approved='1'" 

下表是我的MySQL表設計。我已登錄爲user_id =16到網站。然後user_id=19寄給我一個朋友的請求。然後我批准了它。這裏的一切都很美，但是當我想看到我的朋友時，我也把自己看作是我的朋友。

如何在朋友頁面排除自己？

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嘗試以下

如果我改變這一行

JOIN friendship ON user.id = friendship.receiver_id 

TO

JOIN friendship ON user.id = friendship.sender_id 

這次向我發送友誼請求的另一個用戶將他/她的自己視爲他/她的朋友。

Answer 1

SELECT user.name_surname, user.id, friendship.receiver_id, friendship.sender_id 
FROM user 
JOIN friendship ON user.id = friendship.sender_id OR user.id = friendship.receiver_id 
WHERE (friendship.receiver_id =".$_SESSION["SES_USER_ID"]." OR friendship.sender_id =".$_SESSION["SES_USER_ID"].") 
AND is_approved='1' 
AND user.id != ".$_SESSION["SES_USER_ID"]." 

Answer 2

將

"AND user.id != " . $_SESSION["SES_USER_ID"] 

不能做？所以，你的整個查詢將是：

SELECT user.name_surname, user.id, friendship.receiver_id, friendship.sender_id 
FROM user 
JOIN friendship ON user.id = friendship.receiver_id 
WHERE (friendship.receiver_id =".$_SESSION["SES_USER_ID"]." OR friendship.sender_id =".$_SESSION["SES_USER_ID"] . ") 
AND is_approved='1' 
AND user.id != " . $_SESSION["SES_USER_ID"] 

編輯： 我覺得您的查詢應該是：

SELECT user.name_surname, user.id, friendship.receiver_id, friendship.sender_id 
FROM user 
JOIN friendship ON user.id = friendship.receiver_id 
AND friendship.receiver_id != " . $_SESSION['SES_USER_ID'] . " 
WHERE (friendship.receiver_id =".$_SESSION["SES_USER_ID"]." OR friendship.sender_id =".$_SESSION["SES_USER_ID"] . ") 
AND is_approved='1'