PHP - 關閉準備報告

Question

我指this

我有類似

function getData(){ 
    $query = "SELECT * FROM users WHERE emailID=?"; 
    $stmt = mysqli_prepare($query); 
    if(false == $stmt){ 
     //handleerror Call 
    } 
    $bindParam = mysqli_stmt_bindParam($stmt,"s","a@a.com"); 
    if(false == $bindParam){ 
     **Do I need to close stmt here?** 
     //handleError 
    } 
    $execute = mysqli_stmt_execute($stmt); 
    if(false == $execute){ 
     **Do I need to close stmt here?** 
     //handle error 
    } 
    **Or Stmt will automatically get closed at the end of a function?** 
    } 

任何建議如何關閉語句？

我的疑問是，我應該在哪裏打電話？或者，PHP會在函數結束時自動關閉每條語句？因爲範圍在那裏結束。

我知道如何打電話。但我想知道應該在這種情況下調用，還是會在函數結束時自動關閉php。

Answer 1

$stmt->close(); 

它將關閉該聲明。

Answer 2

如果你自己沒有關閉它，PHP會在腳本/函數結束時執行它。但是當你不再需要它時，你應該「關閉它」。比如說，當發生錯誤時，你可能不需要它。

function getData(){ 
$query = "SELECT * FROM users WHERE emailID=?"; 
$stmt = mysqli_prepare($query); 
if(false == $stmt){ 
    //handleerror Call 
} 
$bindParam = mysqli_stmt_bindParam($stmt,"s","a@a.com"); 
if(false == $bindParam){ 
    //handleError 
    mysqli_close_stmt($stmt) 
    print "Binding failed"; 
} 
$execute = mysqli_stmt_execute($stmt); 
if(false == $execute){ 
    mysqli_close_stmt($stmt) 
    //handle error 
} 
//if you haven't closed, PHP will close it now 
}