嵌套向量如何獲取值

{:measure-value-sets (
    {:benchmark "EUR.EONIA.6Y", :bvalue "0"}), 
:dimensions (
    {:type "Currency", :dvalue "EUR"} 
    {:type "ValueUnderlying_0", :dvalue "21.59999999999811"})} 

{:measure-value-sets (
    {:benchmark "EUR.6M3M.5Y6M", :bvalue "-0"}), 
:dimensions (
    {:type "Currency", :dvalue "EUR"} 
    {:type "ValueUnderlying_0", :dvalue "13.199999999998733"})} 

{:measure-value-sets (
    {:benchmark "EUR.LIBOR.U4", :bvalue "0.03558586"}), 
:dimensions (
    {:type "Currency", :dvalue "EUR"} 
    {:type "ValueUnderlying_0", :dvalue "99.76045398474537"})} 

... snip...

我也有類似的數據集上面，我需要得到基準，bvalue值，dvalue能有人建議最好的方式來遍歷這些殺值是多少？嵌套向量如何獲取值

來源

2014-02-07 redhands

每個地圖都有2個'：dvalue'，你想要哪一個？另外我明白你上面的代碼是這些地圖的矢量，對嗎？ – m0skit0

第一個dvalue – redhands

該數據集無效Clojure。內部列表不被引用，應該可能是向量。通過「殺」你的意思是刪除？ – mac

假設你的數據集的結構爲：

(pprint ds) 

[{:measure-value-sets 
    [{:bvalue "0", :benchmark "EUR.EONIA.6Y"} 
    :dimensions        ; A symbol on its own. Really ?!? 
    [{:dvalue "EUR", :type "Currency"} 
    {:dvalue "21.59999999999811", :type "ValueUnderlying_0"}]]} 
{:measure-value-sets 
    [{:bvalue "-0", :benchmark "EUR.6M3M.5Y6M"} 
    :dimensions 
    [{:dvalue "EUR", :type "Currency"} 
    {:dvalue "13.199999999998733", :type "ValueUnderlying_0"}]]}]

你可以得到所有與bvalues：

(map #(-> % :measure-value-sets first :bvalue) ds)

而且你的第二個dvalues有：

; highly unlikely your structure is correct 
(map #(-> % :measure-value-sets (nth 2) second :dvalue) ds)

而且連同：

(map (juxt 
     #(-> % :measure-value-sets first :bvalue) 
     #(-> % :measure-value-sets (nth 2) second :dvalue)) 
    ds)

它返回

(["0" "21.59999999999811"] ["-0" "13.199999999998733"])

不過，我不認爲你提供的結構是正確的。

來源

2014-02-07 12:31:16 toolkit

嵌套向量如何獲取值

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