2017-01-20 44 views
0

目前我正在開發二手產品的平臺,並正在與laravel合作。在laravel項目中過濾foreach

我只想顯示最大的產品。距當前用戶10公里。 用戶位置和產品位置存儲在數據庫中,我計算它們在將產品發送到視圖的相同控制器中的距離。

現在我想知道我是否可以以某種方式過濾我在此控制器中計算的距離的foreach,以便我可以過濾出距離超過10km的產品。

我覺得我的代碼不好,所以我打開考慮其他選項來實現這一點。

控制器功能:

public function getNearest() 
    { 
     $products= Product::orderBy('created_at','DESC')->paginate(5); 

     foreach($products as $product) { 

    //function that calculate distance 
     $user = Auth::user(); 
     $address = $product->locatie; //location of product 
     $prepAddr = str_replace(' ','+',$address); 
     $geocode=file_get_contents('https://maps.google.com/maps/api/geocode/json?address='.$prepAddr.'&sensor=false'); 
     $output= json_decode($geocode); 
     $latitude = $output->results[0]->geometry->location->lat; 
     $longitude = $output->results[0]->geometry->location->lng; 

     $address2 = $user->locatie; //location current user 
     $prepAddr2 = str_replace(' ','+',$address2); 
     $geocode2=file_get_contents('https://maps.google.com/maps/api/geocode/json?address='.$prepAddr2.'&sensor=false'); 
     $output2= json_decode($geocode2); 
     $latitude2 = $output2->results[0]->geometry->location->lat; 
     $longitude2 = $output2->results[0]->geometry->location->lng; 


     $coordinate1 = new Coordinate($latitude, $longitude); //location current user 
     $coordinate2 = new Coordinate($latitude2, $longitude2); //location product 

     $calculator = new Vincenty(); 
     $d = $calculator->getDistance($coordinate1, $coordinate2); 
     $distance =$d/1000; 

       $product->distance = round($distance); 

     if($product->distance>10){ 
      //dont show product above 10km and filter foreach somehow? 
     } 
     } 


     return view('welcome',compact('products')); 
    } 

查看:

@foreach ($products as $product) 
    <div class="col-lg-3 margin-tb"> 
     <img src="/uploads/products/{{ $product->afbeelding }}"> 
     <p>{{ $product->name}}</p> 
     <p>{{ $product->details}}</p> 
     <p>{{ $product->price}}</p> 
     <p>{{ $product->locatie}}</p> 
     <p>{{ $product->distance}} km van jouw locatie</p> 




     <a href="/Zoekertjes/{{ $product->id }}">bekijken</a> 

    </div> 
    @endforeach 

回答

0

不是最優化的解決方案,但它應該工作:

public function getNearest() 
    { 
     $products= Product::orderBy('created_at','DESC')->paginate(5); 
     $user = Auth::user(); 
     $address2 = $user->locatie; //location current user 
     $prepAddr2 = str_replace(' ','+',$address2); 
     $geocode2=file_get_contents('https://maps.google.com/maps/api/geocode/json?address='.$prepAddr2.'&sensor=false'); 
     $output2= json_decode($geocode2); 
     $latitude2 = $output2->results[0]->geometry->location->lat; 
     $longitude2 = $output2->results[0]->geometry->location->lng; 
     $coordinate2 = new Coordinate($latitude2, $longitude2); //location user 

     $products->reject(function($product, $key) use($coordinate2) { 

    //function that calculate distance 

     $address = $product->locatie; //location of product 
     $prepAddr = str_replace(' ','+',$address); 
     $geocode=file_get_contents('https://maps.google.com/maps/api/geocode/json?address='.$prepAddr.'&sensor=false'); 
     $output= json_decode($geocode); 
     $latitude = $output->results[0]->geometry->location->lat; 
     $longitude = $output->results[0]->geometry->location->lng; 

     $coordinate1 = new Coordinate($latitude, $longitude); 
     //location product 

     $calculator = new Vincenty(); 
     $d = round($calculator->getDistance($coordinate1, $coordinate2)/1000); 

     return $d > 10; 
     }); 


     return view('welcome',compact('products')); 
    } 

爲什麼我說這不是最佳的是你」不保證收到5個結果(分頁不起作用)。這是因爲您在PHP級別具有距離邏輯,而不是數據庫級別。一種解決這個問題的方法是計算產品,如果它們是< 5,則獲取更多結果並計算距離,如果它們大於5,則取前5個。當然,最好的方法是在DB層面處理距離計算