如何從表

Question

我從3個不同的表中選擇喜歡的一些值的底部選擇，

$result=mysql_query("select a.party_name, a.app_date, a.receive_date, a.case_type, c.order_date from party_details a, case_decision b, assign_advocate c where MONTHNAME(b.date)='$month' and YEAR(b.date)='$year' and a.partyid=b.party_id and a.partyid=c.party_id and c.status='1'"); 

但我想從底部只選擇1的值或者在表C的遞減順序說（case_decision ）。

我該怎麼做。請告訴我。感謝名單..

Answer 1

'按訂單' 將整理基於列 '降序' 降序排序

$result=mysql_query("select a.party_name, a.app_date, a.receive_date, a.case_type, c.order_date from party_details a, case_decision b, assign_advocate c where MONTHNAME(b.date)='$month' and YEAR(b.date)='$year' and a.partyid=b.party_id and a.partyid=c.party_id and c.status='1' order by a.party_name desc");

Answer 2

使用limit 1order by your_column_name desc

Answer 3

SELECT * FROM table_list ORDER BY col_name DESC LIMIT 1; 

Answer 4

後使用orderby條款

示例（語法）：

SELECT * FROM YOUR_TABLE_NAME ORDER BY YOUR_COL_NAME DESC LIMIT 1; 

，並在你的情況，你應該這樣做：

$result=mysql_query("select a.party_name, a.app_date, a.receive_date, a.case_type, 
c.order_date from party_details a, case_decision b, assign_advocate c where 
MONTHNAME(b.date)='$month' and YEAR(b.date)='$year' and a.partyid=b.party_id and 
a.partyid=c.party_id and c.status='1' **ORDER BY YOUR_COLOUM_NAME DESC LIMIT 1** "); 

Answer 5

Please replce column name as per table design below statement : 

$結果= mysql_query（「選擇a.party_name，a.app_date，a.receive_date，a.case_type， c.order_date from party_details a，case_decision b，assign_advocate c其中 MONTHNAME（b.date）='$ month'和YEAR（b.date）='$ year'和a.partyid = b.party_id和 a.partyid = c.party_id和c.status ='1'按col_name desc limit 1排序「）;

Answer 6

您必須在下面的查詢中將<column>替換爲您希望訂單所依據的列的引用。

select a.party_name, a.app_date, a.receive_date, a.case_type, c.order_date 
from party_details a, case_decision b, assign_advocate c 
where MONTHNAME(b.date)='$month' and YEAR(b.date)='$year' 
and a.partyid=b.party_id and a.partyid=c.party_id and c.status='1' 
order by <column> desc 
limit 1