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運行時嘗試我的手在我的第一個休眠（JPA註解）控制檯應用程序。我一直在試圖解決依賴關係的圈子裏跑來跑去，感覺就像我試圖在颶風中建造一幢房子。另外，我使用maven，我的印象是，這Maven是應該防止這種類型的事情..下反正這是我得到的錯誤：java.lang.NoSuchFieldError的：名字在Hibernate項目
Exception in thread "main" java.lang.NoSuchFieldError: name
at org.slf4j.impl.Log4jLoggerAdapter.<init>(Log4jLoggerAdapter.java:75)
at org.slf4j.impl.Log4jLoggerFactory.getLogger(Log4jLoggerFactory.java:75)
at org.slf4j.LoggerFactory.getLogger(LoggerFactory.java:103)
at org.hibernate.cfg.Configuration.<clinit>(Configuration.java:197)
at org.hibernate.ejb.Ejb3Configuration.<clinit>(Ejb3Configuration.java:107)
at org.hibernate.ejb.HibernatePersistence.createEntityManagerFactory(HibernatePersistence.java:124)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:63)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:47)
at com.deangrobler.hibernatetest.App.main(App.java:14)
這是我的POM文件：
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>com.deangrobler</groupId>
<artifactId>HibernateTest</artifactId>
<version>1.0-SNAPSHOT</version>
<packaging>jar</packaging>
<name>HibernateTest</name>
<url>http://maven.apache.org</url>
<properties>
<project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
</properties>
<dependencies>
<dependency>
<groupId>junit</groupId>
<artifactId>junit</artifactId>
<version>3.8.1</version>
<scope>test</scope>
</dependency>
<dependency>
<groupId>hibernate</groupId>
<artifactId>hibernate-entitymanager</artifactId>
<version>3.4.0.GA</version>
<exclusions>
<exclusion>
<artifactId>ejb3-persistence</artifactId>
<groupId>org.hibernate</groupId>
</exclusion>
</exclusions>
</dependency>
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-core</artifactId>
<version>3.6.10.Final</version>
<exclusions>
<exclusion>
<artifactId>antlr</artifactId>
<groupId>antlr</groupId>
</exclusion>
</exclusions>
</dependency>
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-entitymanager</artifactId>
<version>3.6.10.Final</version>
</dependency>
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-commons-annotations</artifactId>
<version>3.2.0.Final</version>
</dependency>
<dependency>
<groupId>org.hibernate.javax.persistence</groupId>
<artifactId>hibernate-jpa-2.0-api</artifactId>
<version>1.0.1.Final</version>
</dependency>
<dependency>
<groupId>javax.transaction</groupId>
<artifactId>jta</artifactId>
<version>1.1</version>
</dependency>
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-jpamodelgen</artifactId>
<version>1.1.1.Final</version>
<scope>provided</scope>
</dependency>
<dependency>
<groupId>org.slf4j</groupId>
<artifactId>slf4j-log4j12</artifactId>
<version>1.5.5</version>
</dependency>
</dependencies>
</project>
我的註解bean類：
/*
* To change this license header, choose License Headers in Project Properties.
* To change this template file, choose Tools | Templates
* and open the template in the editor.
*/
package com.deangrobler.hibernatetest;
import java.io.Serializable;
import javax.persistence.Basic;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.NamedQueries;
import javax.persistence.NamedQuery;
import javax.persistence.Table;
import javax.xml.bind.annotation.XmlRootElement;
/**
*
* @author Dean Grobler
*/
@Entity
@Table(name = "user")
@XmlRootElement
@NamedQueries({
@NamedQuery(name = "User.findAll", query = "SELECT u FROM User u"),
@NamedQuery(name = "User.findById", query = "SELECT u FROM User u WHERE u.id = :id"),
@NamedQuery(name = "User.findByName", query = "SELECT u FROM User u WHERE u.name = :name")})
public class User implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Basic(optional = false)
@Column(name = "id")
private Integer id;
@Column(name = "name")
private String name;
public User() {
}
public User(Integer id) {
this.id = id;
}
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
@Override
public int hashCode() {
int hash = 0;
hash += (id != null ? id.hashCode() : 0);
return hash;
}
@Override
public boolean equals(Object object) {
// TODO: Warning - this method won't work in the case the id fields are not set
if (!(object instanceof User)) {
return false;
}
User other = (User) object;
if ((this.id == null && other.id != null) || (this.id != null && !this.id.equals(other.id))) {
return false;
}
return true;
}
@Override
public String toString() {
return "com.deangrobler.hibernatetest.User[ id=" + id + " ]";
}
}
如果我能得到這方面的一些幫助，我將感激不盡！
請顯示帶註釋的bean。 – Mauren
你可以顯示你的App.java內容嗎？ –
顯示你的豆類 – BDR