如何結合這兩個查詢？

Question

SELECT htpid AS parentid 
    FROM likehot WHERE htpid 
    IN (SELECT id FROM bultin WHERE DATE >= '1317108749') 
    GROUP BY htpid ORDER BY COUNT(htpid) 
    DESC 

給出結果

parentid 
16060 
16059 
16058 
16057 

等查詢

SELECT app_id,bultin.id,photo_album_id,entcmmnt_id,link_url,youtubeLink, 
     link_image,id, mem_id, subj, body, bultin.date,parentid, 
     from_id, visible_to, image_link,post_via 
FROM bultin 
WHERE id IN ('16062','16059','16058','16057') 
ORDER BY FIELD('16062','16059','16058','16057') 
LIMIT 5 

其實我想同序列的是，在IN所以我用現場操作員

請推薦 感謝

Answer 1

我無法理解nd你的問題..如果你可以請解釋一個更好的方法..我可以給你解決方案..我想說，你不能使用多一個值在第一個查詢「SELECT id FROM bultin WHERE DATE> ='1317108749'）「。還有一件事y不u使用在第一個五年這樣的查詢

值選擇htpid AS的parentid FROM likehot WHERE htpid IN（16062' ， '16059'， '16058'， '16057'）

Answer 2

如果我沒有錯過任何東西，這應該做的工作：

SELECT b.app_id, b.id, b.photo_album_id, b.entcmmnt_id, b.link_url, b.youtubeLink, 
    b.link_image, b.mem_id, b.subj, b.body, b.date, b.parentid, 
    b.from_id, b.visible_to, b.image_link, b.post_via 
FROM bultin AS b 
JOIN (
    SELECT htpid, COUNT(htpid) AS htpid_count 
    FROM likehot 
    GROUP BY htpid ORDER BY COUNT(htpid) 
    DESC 
) AS l ON l.htpid = b.id 
WHERE DATE >= '1317108749' 
ORDER BY l.htpid_count 
LIMIT 5 

讓我知道如果您需要了解此查詢更多詳情。