獲取包含相同的另一列所有MySQL列

Question

嗨可以說我有這樣的一個表：

________________________________________________________ 
| 
| id  |  order | date | item | price| 
------------------------------------------------------- 
|  1   1st  date  i1  10,00| 
|-------------------------------------------------------  
|  2   2nd  date  u2  15,00| 
|------------------------------------------------------- 
|  3   1st  date  i1  20,00| 
|------------------------------------------------------- 
|  4   2nd  date  u2  30,00| 
|------------------------------------------------------- 

我需要得到含有相同的順序名稱項目總金額並打印DISTINCT訂單，如：

order_name - 日期 - 總額。或更好的方式來創建新的表格和存儲每個訂單的總和，並在此表中添加每行的總和ID？

Answer 1

這將真正地返回order_name - date - total sum，假設你date列date

SELECT CONCAT(order, " - ", date, " - ", SUM(price)) as Result 
FROM orders 
GROUP BY `order` 

要增加數量，試試這個：

SELECT CONCAT(order, " - ", date, " - ", CASE WHEN quantity > 1 THEN (quantity * SUM(price)) ELSE SUM(price) END) as Result 
FROM orders 
GROUP BY `order` 

Answer 2

使用GROUP BY：

SELECT SUM(`price`) 
FROM `orders` 
GROUP BY `order` 

http://dev.mysql.com/doc/refman/5.0/en/group-by-functions.html