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對於給定的JSON,如何讓_id將它用作插入另一個JSON的ID?使用Scala從MongoDB獲取_id
試圖獲取如下所示的ID,但不返回正確的結果。
private def getModelRunId(): List[String] = {
val resultsCursor: List[DBObject] =
modelRunResultsCollection.find(MongoDBObject.empty, MongoDBObject(FIELD_ID -> 1)).toList
println("resultsCursor >>>>>>>>>>>>>>>>>> " + resultsCursor)
resultsCursor.map(x => (Json.parse(x.toString()) \ FIELD_ID).asOpt[String]).flatten
}
{
"_id": ObjectId("5269723bd516ec3a69f3639e"),
"modelRunId": ObjectId("5269723ad516ec3a69f3639d"),
"results": [
{
"ClaimId": "526971f5b5b8b9148404623a",
"pricingResult": {
"TxId": 0,
"ClaimId": "Large_Batch_1",
"Errors": [
],
"Disposition": [
{
"GroupId": 1,
"PriceAmt": 20,
"Status": "Priced Successfully",
"ReasonCode": 0,
"Reason": "RmbModel(PAM_DC_1):ProgramNode(Validation CPG):ServiceGroupNode(Medical Services):RmbTerm(RT)",
"PricingMethodologyId": 2,
"Lines": [
{
"Id": 1
}
]
}
]
}
},
你和你當前的代碼得到什麼錯誤?你正在使用哪個驅動程序? – Jean