嵌套的循環：列表 - 沒有得到期望的輸出

Question

我想要做的是估計每個肽即行

我的代碼的得分如下：

import csv, math 

def train_data(fname): 
     #load csv training files 
     peptide= [] 
     allele= [] 
     score = [] 
     with open (fname) as train: 
       reader = csv.DictReader(train, delimiter='\t') 
       for row in reader: 
         peptide.append(row['peptide']) 
         allele.append(row['allele']) 
         score.append(row['score']) 

     return [peptide, allele, score] 

def ff(): 
     peptide, allele, score = train_data('sample.txt') 
     p={'A':(0.074+0.077)/2, 'R':(0.052+0.053)/2, 'N':(0.045+0.044)/2, 'D':(0.054+0.051)/2, 'C':(0.025+0.022)/2, 'Q':(0.034+0.035)/2, 'E':(0.054+0.056)/2, 'G':(0.074+0.074)/2, 'H':(0.026+0.025)/2, 'I':(0.068+0.064)/2, 'L':(0.099+0.096)/2, 'K':(0.058+0.058)/2, 'M':(0.025+0.024)/2, 'F':(0.047+0.048)/2, 'P':(0.039+0.041)/2, 'S':(0.057+0.059)/2, 'T':(0.051+0.053)/2, 'W':(0.013+0.014)/2, 'Y':(0.032+0.033)/2, 'V':(0.073+0.072)/2} 
     for i in range(len(peptide)): 
#    peptide[i]=list(peptide[i]) 
       peptide.append(peptide[i]) 
       for j in range(len(peptide[i])): 
         print(peptide[2][j]) 
         #est_score+=p[peptide[i][j]] 
       print ('---') 
     print(peptide[2][1]) 

if __name__=='__main__': 

     ff() 

當我運行這個代碼我所得到的輸出是所有肽值，即肽[i] [j]在循環中的打印語句，但我想要的是隻得到肽[2] [J]值。 也在循環外面，它工作正常。 打印（肽[2] [1]）給出了O/P完全正常即值 '甲'

我csv文件是這樣的：

peptide score allele 
AAAGAEAGKATTEEQ 0.190842 DRB1_0101 
AAAGAEAGKATTEEQ 0.006301 DRB1_0301 
AAAGAEAGKATTEEQ 0.066851 DRB1_0401 
AAAGAEAGKATTEEQ 0.006344 DRB1_0405 
AAAGAEAGKATTEEQ 0.035130 DRB1_0701 
AAAGAEAGKATTEEQ 0.006288 DRB1_0802 
AAAGAEAGKATTEEQ 0.176268 DRB1_0901 
AAAGAEAGKATTEEQ 0.042555 DRB1_1101 
AAAGAEAGKATTEEQ 0.114855 DRB1_1302 
AAAGAEAGKATTEEQ 0.006377 DRB1_1501 
AAAGAEAGKATTEEQ 0.006296 DRB3_0101 
AAAGAEAGKATTEEQ 0.006313 DRB4_0101 
AAAGAEAGKATTEEQ 0.070413 DRB5_0101 

什麼我想要做的是估計每個肽的得分，即排 並非所有行一起使用： est_score + = p [肽[i] [j]]

Answer 1

import csv, math 

p={'A':(0.074+0.077)/2, 'R':(0.052+0.053)/2, 'N':(0.045+0.044)/2, 'D':(0.054+0.051)/2, 'C':(0.025+0.022)/2, 'Q':(0.034+0.035)/2, 'E':(0.054+0.056)/2, 'G':(0.074+0.074)/2, 'H':(0.026+0.025)/2, 'I':(0.068+0.064)/2, 'L':(0.099+0.096)/2, 'K':(0.058+0.058)/2, 'M':(0.025+0.024)/2, 'F':(0.047+0.048)/2, 'P':(0.039+0.041)/2, 'S':(0.057+0.059)/2, 'T':(0.051+0.053)/2, 'W':(0.013+0.014)/2, 'Y':(0.032+0.033)/2, 'V':(0.073+0.072)/2} 

def train_data(fname): 
     #load csv training files 
     peptide= [] 
     allele= [] 
     score = [] 
     with open (fname) as train: 
       reader = csv.DictReader(train, delimiter='\t') 
       for row in reader: 
         peptide.append(row['peptide']) 
         allele.append(row['allele']) 
         score.append(row['score']) 

     return [peptide, allele, score] 

def ff(): 
     peptide, allele, score = train_data('peptide.txt') 
     for i in range(len(peptide)): 
       est_score = 0 
       for char in peptide[i]: 
        est_score += p[char] 
       print("est_score: " + str(est_score), "\t: read_score: " + str(score[i])) 
       print ('---') 
     print(peptide[2][1]) 

if __name__=='__main__': 

     ff() 

est_score總是相同的，因爲在您提供的文件中，肽在每一行中都是相同的。這將打印：

est_score: 0.9625000000000001 : read_score: 0.190842 
--- 
est_score: 0.9625000000000001 : read_score: 0.006301 
--- 
est_score: 0.9625000000000001 : read_score: 0.066851 
--- 
est_score: 0.9625000000000001 : read_score: 0.006344 
--- 
est_score: 0.9625000000000001 : read_score: 0.035130 
--- 
est_score: 0.9625000000000001 : read_score: 0.006288 
--- 
est_score: 0.9625000000000001 : read_score: 0.176268 
--- 
est_score: 0.9625000000000001 : read_score: 0.042555 
--- 
est_score: 0.9625000000000001 : read_score: 0.114855 
--- 
est_score: 0.9625000000000001 : read_score: 0.006377 
--- 
est_score: 0.9625000000000001 : read_score: 0.006296 
--- 
est_score: 0.9625000000000001 : read_score: 0.006313 
--- 
est_score: 0.9625000000000001 : read_score: 0.070413 
--- 
A 

Answer 2

對我來說，只是打印peptide[2][j]，但它在打印多次，這是你想要的嗎？

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python2和python3都給了我相同的結果。