如何在同一對象的構造函數中調用不同的構造函數？

Question

我有一個重載構造函數的類。我想對代碼進行重新分解，以便對構造函數的一種形式的調用將參數轉換爲另一種構造函數接受的格式，然後調用它。

這裏是我目前擁有的三個構造函數的代碼：

/// <summary> 
/// Original Constructor accepting a single dataset 
/// </summary> 
/// <param name="theData"> The dataset containing the tables to be displayed</param>  
public DataForm(System.Data.DataSet theData) 
{ 
    InitializeComponent(); 

    // Ensure a DataSets has been passed for display 
    if (theData != null) 
    { 
     // Create a new list and add the single dataset to it 
     List<DataSet> tempDataList = new List<DataSet>(); 
     tempDataList.Add(theData); 

     // Assign the list of datasets to the member variable 
     this.m_DSList = tempDataList; 
    } 

    CreateTabPages(); 
} 

/// <summary> 
/// Construct the form with tab pages assigned for each dataset 
/// </summary> 
/// <param name="DataArray">A collection of datasets, each to be displayed on their own tab page</param> 
public DataForm(DataSet[] DataArray) 
{ 
    InitializeComponent(); 

    // Ensure some DataSets have been passed for display 
    if (DataArray != null && DataArray.Length > 0) 
    { 
     // Assign the list of datasets to teh member variable 
     this.m_DSList = new List<DataSet>(DataArray); 
    } 

    CreateTabPages(); 
} 

/// <summary> 
/// Construct the form with tab pages assigned for each dataset 
/// </summary> 
/// <param name="DataList">A collection of datasets, each displayed on their own tab page</param> 
public DataForm(List<System.Data.DataSet> DataList) 
{ 
    InitializeComponent(); 

    // Assign the list of datasets to teh member variable 
    this.m_DSList = DataList; 

    CreateTabPages(); 
} 

正如你可以看到有重複代碼的前兩個構造函數，因此重新分解。

我知道我可以有一個確實的對象初始化的方法和調用這個從每個構造函數，但是這似乎並不很優雅。

任何人都可以點我在正確的方向？ 謝謝。

Answer 1

試試這個

public DataForm(System.Data.DataSet theData): this(new List<System.Data.DataSet>{theData}){} 

public DataForm(DataSet[] DataArray): this(DataArray.ToList()){} 

public DataForm(List<System.Data.DataSet> DataList) 
{ 
    InitializeComponent(); 

    // Assign the list of datasets to teh member variable 
    this.m_DSList = DataList; 

    CreateTabPages(); 
} 

Answer 2

public DataForm() 
     { 
      InitializeComponent(); 
     } 
     public DataForm(DataSet theData): this() 
     { 
      this.m_DSList= (theData!=null) ? new List<DataSet>{theData}:null; 
     } 
     public DataForm(DataSet[] DataArray):this() 
     { 
      this.m_DSList= (DataArray!=null && DataArray.Length > 0) ? new List<DataSet>(DataArray):null; 
     } 
     public DataForm(List<DataSet> DataList):this() 
     {   
      this.m_DSList = DataList; 
     } 
     //Take this method out from constructor and for a better design but not mandatory 
     public void CreateTabPages() 
     { 
     }