蜂巢多個計數（有和沒有DISTINCT）產生不好的輸出

-1

Select id,count(distinct CASE WHEN unix_timestamp(m_date) BETWEEN unix_timestamp(cast(date_sub(cast('2017-02-01' as date),60) as date)) AND unix_timestamp(cast('2017-02-01' as date)) THEN m_date ELSE 0 END) 
     ,count(CASE WHEN unix_timestamp(m_date) BETWEEN unix_timestamp(cast(date_sub(cast('2017-02-01' as date),60) as date)) AND unix_timestamp(cast('2017-02-01' as date)) THEN m_date ELSE 0 END) 
From DB.TABLE2 GROUP BY id limit 10;

，這讓我smthg喜歡：

111007001007633 1  1 
111007001029793 1  1 
111007001000521 1  11 
111007001000794 1  1 
111007001000273 3  13 
111007001001032 1  1 
111007001025874 1  4 
111007001001792 1  7 
111007001029181 1  1 
111007001000141 16  96

但當我添加其他數：

Select id,count(distinct CASE WHEN unix_timestamp(m_date) BETWEEN unix_timestamp(cast(date_sub(cast('2017-02-01' as date),60) as date)) AND unix_timestamp(cast('2017-02-01' as date)) THEN m_date ELSE 0 END) 
     ,count(CASE WHEN unix_timestamp(m_date) BETWEEN unix_timestamp(cast(date_sub(cast('2017-02-01' as date),60) as date)) AND unix_timestamp(cast('2017-02-01' as date)) THEN m_date ELSE 0 END) 
     ,count(distinct CASE WHEN unix_timestamp(m_date) BETWEEN unix_timestamp(cast(date_sub(cast('2017-02-01' as date),15) as date)) AND unix_timestamp(cast('2017-02-01' as date)) THEN m_date ELSE 0 END) 
     ,count(CASE WHEN unix_timestamp(m_date) BETWEEN unix_timestamp(cast(date_sub(cast('2017-02-01' as date),15) as date)) AND unix_timestamp(cast('2017-02-01' as date)) THEN m_date ELSE 0 END) 
From DB.TABLE2 GROUP BY id limit 10;

它返回的東西不像這樣：

111007001010439 0  0  1  0 
111007001026963 0  0  1  0 
111007001028001 0  0  1  0 
111007001032987 0  0  1  0 
111007001048710 0  0  1  0 
111007001052415 0  0  1  0 
111007002008374 0  0  1  0 
111007003000644 0  0  1  0 
111007003002210 0  0  1  0

我在hadoop集羣上工作，如果它是由map reduce造成的，我不會。

由於

[編輯]

正如我回答到@pashaz評論，第一個問題是由兩個相同的查詢，其用於不同的和0得到1的結果（有和沒有不同）因爲不明顯。

第二個問題是兩個不同查詢和兩個非重複查詢之間的結果。如果您檢查時間戳，則會看到第一個查詢包含秒數，因爲前兩個數字計算「2017-02-01」和之間60天之間的出現次數，第二次計算「2017-02-01」和15天前。

[更新]

如果我把一個WHERE子句，它的工作原理

WHERE id="111007001007633" OR id="271011604404359" OR id="122213250512607" OR id="111007001033217" 


111007001033217 0  0  0  0  0  0 
122213250512607 1  3  8  14  0  0 
271011604404359 12  21  26  42  5  9 
111007001007633 14  19  24  34  5  5

LIMIT子句似乎是問題。

來源

2017-04-14 Indy McCarthy

是第二個查詢返回每個單行的結果（0,0,1,0）？如果對第一個查詢返回「有效」結果的行之一運行第二個查詢，會發生什麼情況，如111007001000141？ – Andrew

@Andrew我不知道，我會檢查並給你結果ASAP –