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我期待找到使用jQuery橫移一定格,如果該div有一個特定的類,顯示一個警告.. http://jsfiddle.net/gfA4F/1/jQuery遍歷.closest()。find()不起作用? (帶的jsfiddle)
這裏是HTML(外格爲模板的目的):
<div class="thisness">
<div class="container">
<div class="btn-group dropdown options-btns mark-read">
<button type="button" class="btn btn-sm options-btn dropdown-toggle" data-toggle="dropdown">
<span class="glyphicon glyphicon-unchecked"></span>
</button>
<ul class="dropdown-menu" role="menu">
<li>>Item1</li>
<li>>Item2</li>
<li>>Item3</li>
</ul>
</div>
</div>
<div class="container">
<div class="btn-group dropdown options-btns mark-read">
<button type="button" class="btn btn-sm options-btn dropdown-toggle" data-toggle="dropdown">
<span class="glyphicon glyphicon-check"></span>
</button>
<ul class="dropdown-menu" role="menu">
<li>>Item1</li>
<li>>Item2</li>
<li>>Item3</li>
</ul>
</div>
</div>
...
</div>
,這裏是試圖運行,它需要加以糾正:
$(document).ready(function(){
$(".thisness").on("show.bs.dropdown", ".options-btns", function() {
var $this = $(this);
var $that = $this.closest('.container').find('.glyphicon');
if ($that.hasClass('.glyphicon-unchecked')) {alert('unchecked');}
else if ($that.hasClass('.glyphicon-check')) {alert('check');}
});
});
更新吧:)不知道你有多個'.container'所以,是的,你確實需要'closest' – imbondbaby
真棒!很好,趕上,謝謝你 – StackThis