生成PI超過2315位

Question

我設法讓我的代碼工作，所以它產生PI：

while True: 
     print("how many digits of pi would you like?") 


     def make_pi(): 
      q, r, t, k, m, x = 1, 0, 1, 1, 3, 3 
      for j in range(1000000): 
       if 4 * q + r - t < m * t: 
        yield m 
        q, r, t, k, m, x = 10 * q, 10 * (r - m * t), t, k, (10 * (3 * q + r)) // t - 10 * m, x 
       else: 
        q, r, t, k, m, x = q * k, (2 * q + r) * x, t * x, k + 1, (q * (7 * k + 2) + r * x) // (t * x), x + 2 


     digits = make_pi() 
     pi_list = [] 
     my_array = [] 

     for i in make_pi(): 
      my_array.append(str(i)) 

     number = int(input())+2 
     my_array = my_array[:1] + ['.'] + my_array[1:] 
     big_string = "".join(my_array[: number ]) 
     print("here is the string:\n %s" % big_string) 

但是不管我多麼增加range的代碼只有一個最大的圓周率2315位輸出小數點後

how can I fix this? 

Answer 1

怎樣使參數化make_pi生成器接受數位數？

事情是這樣的：

def make_pi(num_digits): 
    q, r, t, k, m, x = 1, 0, 1, 1, 3, 3 
    for j in range(num_digits): 
     if 4 * q + r - t < m * t: 
      yield m 
      q, r, t, k, m, x = 10 * q, 10 * \ 
       (r - m * t), t, k, (10 * (3 * q + r)) // t - 10 * m, x 
     else: 
      q, r, t, k, m, x = q * \ 
       k, (2 * q + r) * x, t * x, k + \ 
       1, (q * (7 * k + 2) + r * x) // (t * x), x + 2 


num_digits = 10000 
pi = "".join([str(d) for d in make_pi(num_digits)]) 
print("{0}.{1}".format(pi[:1], pi[1:]))