連接到服務器的數據庫和pasrse數據usind JSON解析器

這裏是我的代碼，我嘗試連接到服務器的數據庫，但給人的異常socketexception網絡NT可達但它工作本地主機請幫助我笏是DIS代碼連接到服務器的數據庫和pasrse數據usind JSON解析器

package com.example.test2; 

import java.io.BufferedReader; 
import java.io.InputStream; 
import java.io.InputStreamReader; 

import org.apache.http.HttpEntity; 
import org.apache.http.HttpResponse; 
import org.apache.http.client.HttpClient; 
import org.apache.http.client.methods.HttpPost; 
import org.apache.http.impl.client.DefaultHttpClient; 
import org.json.JSONArray; 
import org.json.JSONObject; 

//import android.R; 
import android.annotation.SuppressLint; 
import android.app.Activity; 
import android.os.Bundle; 
import android.os.StrictMode; 
//import android.os.StrictMode; 
import android.util.Log; 
import android.widget.TextView; 
import android.widget.Toast; 

public class MainActivity extends Activity { 
    /** Called when the activity is first created. */ 

    TextView resultView; 
    @SuppressLint("NewApi") 
    @Override 
    public void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.activity_main); 
     resultView = (TextView) findViewById(R.id.result); 
     //StrictMode.enableDefaults(); 
     getData(); 
    } 

    public void getData(){ 
     String result = ""; 
     InputStream isr = null; 
     try{ 
      HttpClient httpclient = new DefaultHttpClient(); 
      Toast.makeText(getApplicationContext() , "1" ,Toast.LENGTH_SHORT).show(); 

      HttpPost httppost = new HttpPost("http://localhost/xampp/connect.php"); 
      String str=httppost.toString();//YOUR PHP SCRIPT ADDRESS 
      Toast.makeText(getApplicationContext() , str ,Toast.LENGTH_LONG).show(); 

      HttpResponse response = httpclient.execute(httppost); 

      Toast.makeText(getApplicationContext() , "3" ,Toast.LENGTH_SHORT).show(); 

      HttpEntity entity = response.getEntity(); 
      isr = entity.getContent(); 
    } 
    catch(Exception e){ 
      Log.e("log_tag", "Error in http connection "+e.toString()); 
      resultView.setText("Couldnt connect to database"); 
    } 
    //convert response to string 
    try{ 
      BufferedReader reader = new BufferedReader(new InputStreamReader(isr,"iso-8859-1"),8); 
      StringBuilder sb = new StringBuilder(); 
      String line = null; 
      while ((line = reader.readLine()) != null) { 
        sb.append(line + "\n"); 
      } 
      isr.close(); 

      result=sb.toString(); 
    } 
    catch(Exception e){ 
      Log.e("log_tag", "Error converting result "+e.toString()); 
    } 

    //parse json data 
    try { 
     String s = ""; 
     JSONArray jArray = new JSONArray(result); 

     for(int i=0; i<jArray.length();i++){ 
      JSONObject json = jArray.getJSONObject(i); 
      s = s + 
        "ID : "+json.getString("id")+" \nNAME : "+json.getString("name")+"\n\n"; 
     } 

     resultView.setText(s); 

    } catch (Exception e) { 
    // TODO: handle exception 
     Log.e("log_tag", "Error Parsing Data "+e.toString()); 
    } 

    } 


}

大問題

即使我已經取得互聯網許可仍然需要任何權限

來源

2013-08-19 user2694271

不能在真正的服務器上工作，但在本地主機上工作？你能給我們真正的服務器鏈接嗎？也許問題是在真正的服務器 –

有什麼錯誤？ – Exceptional

你有你自己的域名？ – Exceptional

如果您將getData（）放入線程中，問題將得到解決。

例如：

new Thread(new Runnable(){ 
    @Override 
    public void run() { 
     getData(); // If you want to update UI, please put Update UI into runOnUIThread 
    } 
});

但我不建議你使用這種方式。請使用AsyncTask來解決。

閱讀更多我對這個問題的回答：What is the relationship between AsyncTask and Activity?

來源

2013-08-19 03:39:25 Luc

的問題就在這裏：

HttpPost httppost = new HttpPost("http://localhost/xampp/connect.php");

更改本地主機的IP地址是這樣的：

HttpPost httppost = new HttpPost("your ip address /connect.php");// where your ip address will be something like 192.168.14.4

要獲得烏爾IP地址轉到開始>輸入cmd>然後在出現的屏幕上鍵入ipconfig。如果你連接到WIFI下的IPV4下的WIFI。也請確保你把服務器在線！

來源

2013-08-19 04:38:26

"http://localhost/xampp/connect.php"

你不能把本地主機，而不是把你的IP地址在那裏。

來源

2013-08-19 22:09:13

連接到服務器的數據庫和pasrse數據usind JSON解析器

回答

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