Hibernate無法找到它剛剛創建的表的類的映射

Question

我有休眠創建我的數據庫模式。它能夠很好地創建表，但指定的查詢不會編譯，因爲它聲明對象未映射。

整個應用程序是註釋和配置驅動：沒有.xml文件。

下面是相關配置部分：

properties = new Properties(); 
properties.setProperty("hibernate.connection.driver_class", "org.postgresql.Driver"); 
properties.setProperty("hibernate.connection.url", con); 
properties.setProperty("hibernate.connection.username", user); 
properties.setProperty("hibernate.connection.password", pass); 
properties.setProperty("hibernate.dialect", "org.hibernate.dialect.PostgreSQLDialect"); 
properties.setProperty("hibernate.current_session_context_class","thread"); 
properties.setProperty("hibernate.hbm2ddl.auto","create"); 

Configuration config = new Configuration(); 
config.setProperties(properties); 
config.addAnnotatedClass(Player.class); 
SessionFactory factory = config.buildSessionFactory(); 

我的播放器類已初具雛形，現在 - 它有一個像姓名和身份證一些參數。它高興地將這些轉換成適當的表格。

@Entity 
@NamedQueries({ 
    @NamedQuery(name="verifyPlayerByUuid", query="SELECT name FROM player WHERE uuid = :uuid"), 
    @NamedQuery(name="verifyPlayerByName", query="SELECT name FROM player WHERE name = :name"), 
    @NamedQuery(name="obtainPlayerByUuid", query="FROM player WHERE uuid = :uuid"), 
}) 
public class Player { 
    // impl here 
} 

當我運行它，我得到這個。請注意，我修剪了樣板時間戳和休眠包名稱，以便爲相關消息留出更多空間。爲了更好地組織數據，我還採取了格式化信息的自由 - 這隻涉及空白的添加。

[timestamp] [hib].hbm2ddl.SchemaExport - HHH000227: Running hbm2ddl schema export 
[timestamp] [hib].hbm2ddl.SchemaExport - HHH000230: Schema export complete 

[timestamp] [hib].SessionFactoryImpl  - HHH000177: Error in named query: verifyPlayerByUuid 
org.hibernate.hql.internal.ast.QuerySyntaxException: 
    player is not mapped [SELECT name FROM player WHERE uuid = :uuid] 

[timestamp] [hib].SessionFactoryImpl  - HHH000177: Error in named query: obtainPlayerByUuid 
org.hibernate.hql.internal.ast.QuerySyntaxException: 
    player is not mapped [FROM player WHERE uuid = :uuid] 

[timestamp] [hib].SessionFactoryImpl  - HHH000177: Error in named query: verifyPlayerByName 
org.hibernate.hql.internal.ast.QuerySyntaxException: 
    player is not mapped [SELECT name FROM player WHERE name = :name] 

Answer 1

您需要使用的是映射實體

config.addAnnotatedClass(Player.class); 
... 
FROM Player WHERE uuid = :uuid 

同樣，uuid需要是類的字段的類的名稱。