在BASH中，是否可以在函數體中獲取函數名？

Question

在BASH中，是否可以在函數體中獲取函數名？以下面的代碼爲例，我想在它的主體中打印函數名稱「Test」，但「$ 0」似乎是指腳本名稱而不是函數名稱。那麼如何獲得函數名？

#!/bin/bash 

function Test 
{ 
    if [ $# -lt 1 ] 
    then 
     # how to get the function name here? 
     echo "$0 num" 1>&2 
     exit 1 
    fi 
    local num="${1}" 
    echo "${num}" 
} 

# the correct function 
Test 100 

# missing argument, the function should exit with error 
Test 

exit 0 

Answer 1

嘗試${FUNCNAME[0]}。該數組包含當前的調用堆棧。引用手冊頁：

FUNCNAME 
      An array variable containing the names of all shell functions 
      currently in the execution call stack. The element with index 0 
      is the name of any currently-executing shell function. The bot‐ 
      tom-most element is "main". This variable exists only when a 
      shell function is executing. Assignments to FUNCNAME have no 
      effect and return an error status. If FUNCNAME is unset, it 
      loses its special properties, even if it is subsequently reset. 

Answer 2

的函數的名稱是在${FUNCNAME[ 0 ]} FUNCNAME是包含在調用堆棧的功能的全部名字的數組，所以：

 
$ ./sample 
foo 
bar 
$ cat sample 
#!/bin/bash 

foo() { 
     echo ${FUNCNAME[ 0 ]} # prints 'foo' 
     echo ${FUNCNAME[ 1 ]} # prints 'bar' 
} 
bar() { foo; } 
bar