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我的第一個問題並不那麼清楚,所以我刪除它,這裏是一個重新定義; 我有兩個數組:基於一個公共密鑰合併許多數組php
$open = array(array("FAI1","34"),array("FAI2","34"),array("FAI3","34"));
$click = array(array("FAI2","52"),array("FAI1","68"),array("FAI3","99"));
$unsubscribe = array(array("FAI2","103"),array("FAI3","67"),array("FAI1","102"));
$def_sent = array(array("FAI1","34",24),array("FAI2","34",23),array("FAI3","34",27));
$SB = array(array("FAI2","103"),array("FAI3","67"),array("FAI1","102"));
$HB = array(array("FAI2","103"),array("FAI3","67"),array("FAI1","102"));
我搜索了一個函數來合併它們,並得到這樣的結果:
$result = array(array("FAI1",34,68,102,34,24,102,102)
,array("FAI2","34",23.....),
array("FAI3","34",27....));
而要做到這一點,我使用的功能,PHP的在線文檔中,這就是功能但
function array_merge_recursive() {
$arrays = func_get_args();
$base = array_shift($arrays);
foreach ($arrays as $array) {
reset($base);
while (list($key, $value) = @each($array)) {
if (is_array($value) && @is_array($base[$key])) {
$base[$key] = array_merge_recursive($base[$key], $value);
} else {
$base[$key] = $value;
}
}
}
return $base;
}
不是得到上述結果我得到這個:
FAI1|34
FAI2|34
FAI3|34
FAI2|52
FAI1|68
FAI3|99
...
所以我需要一些幫助來重新配置這個函數來獲得預期的結果。
是的,它可以幫助很多謝謝! – Ahmadhc