2013-09-25 114 views
-3

My While循環在下面的代碼中不起作用。當我註釋掉while行和兩個括號時,while循環中的所有內容都回聲良好。只要我取消註釋while循環並再次運行它,我就沒有錯誤,但所有內部回聲都消失了。PHP while while循環未執行

case 'search': 

echo "searching".$firstname; 


$sqlsearch="SELECT * FROM Customer WHERE firstname='$firstname'"; 

$sim = mysql_query($conndb, $sqlsearch); 

while($row = mysql_fetch_array($sim)) 
{ 
echo "firstname: ".$row['firstname']."<br>"; 
echo "lastname: ".$row['lastname']."<br>"; 
echo "phone: ".$row['phone']."<br>"; 
echo "address: ".$row['address']."<br>"; 
echo "city: ".$row['city']."<br>"; 
echo "state: ".$row['state']."<br>"; 
echo "zip: ".$row['zip']."<br>"; 
echo $sqlsearch; 
} 

echo "<br>"; 
echo "seaching 2"; 
break; 
+0

做了'回聲$ firstname'生產什麼? – James

+0

不,除非你註釋掉while部分,while循環裏面什麼都沒有執行。 – user519670

+0

以上代碼中的第二行代碼。即'$ firstname'在它遇到查詢之前是否保存了任何值? – James

回答

-1

爲了解決這個問題,我不得不改變線路而($行= mysql_fetch_array($ SIM))改爲($行== mysql_fetch_array(SIM $))