從多個foreach循環創建一個對象

Question

我正在嘗試爲單個玩家創建一個對象，該玩家擁有所有可用季節中的所有玩家排名。

我一直在獲取信息並通過它進行迭代。每個循環都可以工作，但我認爲在迭代時覆蓋部分對象。我不確定如何在不覆蓋部分對象的情況下獲取所有信息。

這是我到目前爲止有：

var playerObj; 
var username = page.find('.profile_player-name').text(); 
if(username) { 
    var seasons = page.find('.profile_seasons .tab-pane'); 
    var seasonsObj; 
    $.each(seasons, function(i) { 
     var statsObj; 
     var season = $(seasons[i]); 
     var season_number = season.attr('id'); 
     var season_playlists = season.find('.row > .col-md-3'); 
     $.each(season_playlists, function(i) { 
      var playlist = $(season_playlists[i]); 
      var playlist_title = playlist.find('.panel-title').text(); 
      var playlist_rating = playlist.find('.profile_tier-name').text().match(/\d+/g); 
      if(playlist_rating) { 
       playlist_rating = playlist_rating[0]; 
      } 
      var playlist_rank = playlist.find('.profile_tier-name strong').text(); 
      var playlist_rank_icon = "http://rocketleaguestats.com/" + playlist.find('img').attr('src'); 
      statsObj = { 
       title:playlist_title, 
       rating:playlist_rating, 
       rank: {rank_name:playlist_rank, rank_icon:playlist_rank_icon} 
      }; 
      console.log(statsObj); 
     }); 
    }); 
} else { 
    return false; 
} 

這應返回是這樣的：

object = { 
    username: "name", 
    seasons: 
     season_1: 
      rank: 
       rank_name: "Gold", 
       rank_icon: http://....jpg, 
      rating: "800", 
      title: "Ranked Standard" 
     season_2: 
      rank: 
       rank_name: "Gold", 
       rank_icon: http://....jpg, 
      rating: "800", 
      title: "Ranked Standard" 
     season_3: 
      rank: 
       rank_name: "Gold", 
       rank_icon: http://....jpg, 
      rating: "800", 
      title: "Ranked Standard" 
} 

但我不知道如何添加每個不同的季節，因爲它是自己的一片的對象，具有不同的變量名稱（season_1 vs season_3）。

如何動態添加每個season_#作爲對象的自己的一部分？可能會有一到多個季節。

Answer 1

如果您需要向對象添加屬性，但屬性名稱是可變的，則可以使用[]語法。就你而言，你可以通過幾個簡單的改變來達到你想要的。

首先，只是初始化對象

var seasonsObj = { 
    username: username, 
    seasons: {} 
}; 

然後，在你的循環，你可以將屬性添加到seasonsObj.seasons這樣的：

seasonObj.seasons['season_' + i] = statsObj; 

Answer 2

定義一個變量說data，現在添加一個鍵值一對：

var data = {}; 
var playerObj; 
var username = page.find('.profile_player-name').text(); 
if(username) { 
    var seasons = page.find('.profile_seasons .tab-pane'); 
    var seasonsObj; 
    $.each(seasons, function(i) { 
     var statsObj; 
     var season = $(seasons[i]); 
     var season_number = season.attr('id'); 
     var season_playlists = season.find('.row > .col-md-3'); 
     $.each(season_playlists, function(i) { 
      var playlist = $(season_playlists[i]); 
      var playlist_title = playlist.find('.panel-title').text(); 
      var playlist_rating = playlist.find('.profile_tier-name').text().match(/\d+/g); 
      if(playlist_rating) { 
       playlist_rating = playlist_rating[0]; 
      } 
      var playlist_rank = playlist.find('.profile_tier-name strong').text(); 
      var playlist_rank_icon = "http://rocketleaguestats.com/" + playlist.find('img').attr('src'); 
      statsObj = { 
       title:playlist_title, 
       rating:playlist_rating, 
       rank: {rank_name:playlist_rank, rank_icon:playlist_rank_icon} 
      }; 
      data["season_"+(i+1)] = statsObj; // Add a key value pair here. 
      console.log(statsObj); 
     }); 
    }); 
} else { 
    return false; 
}