我正在使用OAuth-Sample-Client代碼通過鏈接邀請API從電子郵件地址發送邀請。 我已經創建了與開發者網站中描述的相同的主體,但是現在我得到了401錯誤,我已經搜索了很多關於它的信息,但是沒有得到任何解決方案讓我從任何網站或論壇中獲得它。 我的回覆如下。LinkedIn Invitation API錯誤401 [未授權] -iPhone sdk
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<error>
<status>401</status>
<timestamp>1351159386437</timestamp>
<request-id>YX4NRU3S7J</request-id>
<error-code>0</error-code>
<message>[unauthorized]. OAU:ron8e8nko3te|e0a96317-dfdc-44fb-b427-5655e02f97ed|*01|*01:1351159294:dRCDN6b3K9F/mwWAaByKZQPgeVw=</message>
</error>
這裏我JSON字符串會是這樣的:
{ 「體」: 「說是的!」, 「主題」: 「邀請 連接」, 「收件人」:{ 「值」:[{ 「人」:{ 「第一名」: 「測試」, 「最後的名稱」: 「測試」, 「_路徑」: 「/ people/[email protected]」}}] },「item-content」:{「invitation-request」:{「connect-type」:「friend」}}}
我已經使用下面的代碼發送邀請。
- (IBAction)postButton_TouchUp:(UIButton *)sender
{
[statusTextView resignFirstResponder];
NSURL *url = [NSURL URLWithString:@"http://api.linkedin.com/v1/people/~/mailbox"];
OAMutableURLRequest *request =
[[OAMutableURLRequest alloc] initWithURL:url
consumer:oAuthLoginView.consumer
token:oAuthLoginView.accessToken
callback:nil
signatureProvider:[[OAHMAC_SHA1SignatureProvider alloc] init]];
[request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
NSDictionary *temp=[[NSDictionary alloc]initWithObjectsAndKeys:@"/people/[email protected]",@"_path",@"test",@"first-name",@"test",@"last-name", nil];
NSDictionary *temp2=[[NSDictionary alloc] initWithObjectsAndKeys:temp,@"person",nil];
NSArray *arr2=[[NSArray alloc]initWithObjects:temp2, nil];
NSDictionary *value=[[NSDictionary alloc]initWithObjectsAndKeys:arr2,@"values", nil];
NSDictionary *dict3=[[NSDictionary alloc]initWithObjectsAndKeys:@"friend",@"connect-type",nil];
NSDictionary *dict4=[[NSDictionary alloc] initWithObjectsAndKeys:dict3,@"invitation-request", nil];
NSDictionary *dict=[[NSDictionary alloc]initWithObjectsAndKeys:dict4,@"item-content",@"Say yes!",@"body",@"Invitation to connect.",@"subject",value,@"recipients", nil];
NSLog(@"%@",[dict description]);
NSString *updateString = [dict JSONString];
[request setHTTPBodyWithString:updateString];
[request setHTTPMethod:@"POST"];
OADataFetcher *fetcher = [[OADataFetcher alloc] init];
[fetcher fetchDataWithRequest:request
delegate:self
didFinishSelector:@selector(postUpdateApiCallResult:didFinish:)
didFailSelector:@selector(postUpdateApiCallResult:didFail:)];
[request release];
}
我被困在這一點,請讓我走出這一點。 - 預先感謝
我有同樣的問題可以幫助解決這個問題嗎? – Nignesh
(postUpdateApiCallResult:didFinish :) (postUpdateApiCallResult:didFail :)我應該怎麼做這個方法..請幫我解決我的問題 – TamilKing