程序掛在FtpWebResponse

Question

第一次張貼海報，長期閱讀。我有一個非常討厭的問題，這讓我感到很緊張。我已經安裝了一個程序，以便在FTP服務器上偵聽新文件，如果這是我下載的新文件。從那裏我開始處理文件中的一些信息等。當我第二次運行我的序列時，我的問題就出現了。也就是說，在我下載的第一個文件中，一切都很完美，但是一旦檢測到新文件並且我的程序嘗試下載它，我的程序就會掛起。

private static void DownloadFile(string s) 
    { 
     try 
     { 
      FtpWebRequest request = (FtpWebRequest)WebRequest.Create("ftp://blabla.com/"+s); 
      request.Method = WebRequestMethods.Ftp.DownloadFile; 
      request.Credentials = new NetworkCredential("xxx" ,"zzz"); 

      using (FtpWebResponse partResponse = (FtpWebResponse)request.GetResponse()) 
      { 
       Stream partReader = partResponse.GetResponseStream(); 

       byte[] buffer = new byte[1024]; 
       FileInfo fi = new FileInfo(path); 
       FileStream memStream = fi.Create(); 
       while (true) 
       { 
        int bytesRead = partReader.Read(buffer, 0, buffer.Length - 1); 
        if (bytesRead == 0) 
         break; 

        memStream.Write(buffer, 0, bytesRead); 
       } 
       partResponse.Close(); 
       memStream.Close(); 
      } 
      Console.WriteLine(DateTime.Now + " file downloaded"); 
      MoveFileToInProgress(s); 
     } 
     catch (Exception e) 
     { 
      Console.WriteLine(e.Message); 
     } 
    } 

它掛在該生產線是這一個： 使用（FtpWebResponse partResponse =（FtpWebResponse）request.GetResponse（））

的原因就在這裏我的方法是靜態的，是因爲我只是運行它在不同的項目來測試它..我的問題是，它怎麼只死在第二個文件？我一直盯着自己幾個小時了！

Answer 1

我不是C＃專家，但我使用此代碼下載從我的FTP文件：

public void Download(string filename) 
    { 
     // I try to download five times before crash 
     for (int i = 1; i < 5; i++) 
     { 
      try 
      { 
       FtpWebRequest ftp = (FtpWebRequest)FtpWebRequest.Create(Global.Path + "/" + filename); 
       ftp.Credentials = new NetworkCredential(User, Pass); 
       ftp.KeepAlive = false; 
       ftp.Method = WebRequestMethods.Ftp.DownloadFile; 
       ftp.UseBinary = true; 
       ftp.Proxy = null; 

       int buffLength = 2048; 
       byte[] buff = new byte[buffLength]; 
       int contentLen; 

       string LocalDirectory = Application.StartupPath.ToString() + "/downloads/" + filename; 
       using (FileStream fs = new FileStream(LocalDirectory, FileMode.Create, FileAccess.Write, FileShare.None)) 
       using (Stream strm = ftp.GetResponse().GetResponseStream()) 
       { 
        contentLen = strm.Read(buff, 0, buffLength); 
        while (contentLen != 0) 
        { 
         fs.Write(buff, 0, contentLen); 
         contentLen = strm.Read(buff, 0, buffLength); 
        } 
       } 

       Process.Start(LocalDirectory); 
       break; 
      } 
      catch (Exception exc) 
      { 
       if (i == 5) 
       { 
        MessageBox.Show("Can't download, try number: " + i + "/5 \n\n Error: " + exc.Message, 
         "Problem downloading the file"); 
       } 
      } 
     } 
    } 

告訴我，如果你的作品:)

Answer 2

我就遇到了這個問題，以及...先嚐試完成您的請求，然後在嘗試檢索響應之前關閉它。這對我很有用（實際上是在閱讀MartinNielsen的評論後嘗試的）。這是我做的。

 // connect to the ftp site 
     FtpWebRequest ftpRequest = (FtpWebRequest)WebRequest.Create(ftpUri); 
     ftpRequest.Method = WebRequestMethods.Ftp.UploadFile; 
     ftpRequest.Credentials = new NetworkCredential(ftpUser, ftpPassword); 

     // setting proxy to null so that it does not go through the proxy 
     ftpRequest.Proxy = null; 

     // get file information 
     StreamReader fileStream = new StreamReader(filePath); 
     byte[] fileBytes = Encoding.UTF8.GetBytes(fileStream.ReadToEnd()); 
     ftpRequest.ContentLength = fileBytes.Length; 
     fileStream.Close(); 

     // open connection to ftp site 
     Stream ftpRequestStream = ftpRequest.GetRequestStream(); 

     // write the file to the stream 
     ftpRequestStream.Write(fileBytes, 0, fileBytes.Length); 

     // close the stream 
     ftpRequestStream.Close(); 

     // get the response from the server 
     FtpWebResponse ftpUploadResponse = (FtpWebResponse)ftpRequest.GetResponse(); 
     string result = ftpUploadResponse.StatusDescription; 

     // close response 
     ftpUploadResponse.Close(); 

     // return response to calling code 
     return result; 

這裏有一對夫婦，我寫這個代碼時使用的資源（不會讓我上傳超過2個，還有更多）

How to: Upload Files with FTP

Uploading a file -- "The requested URI is invalid for this FTP command"