從聲明中接收用戶輸入

Question

我在這裏完全失敗......邏輯似乎設置正確，但while語句中的「響應」表示它在當前上下文中不存在。我在這裏搜索，似乎在這方面找到了同樣的問題。問題是否轉化爲方法？在一個範圍（一般一組括號{ ... }的）宣佈

do 
     { 
      Console.WriteLine("enter a number between 1 and 5"); 
      int x = Convert.ToInt32(Console.ReadLine()); 

      Random r = new Random(); 
      int rr = r.Next(1, 5); 
      Console.WriteLine("Do you want to continue? Please select yes or no."); 
      string response = Convert.ToString(Console.ReadLine()); 
     } while (response == "yes"); 

Answer 1

變量不是該範圍的可訪問的外部。您已在內聲明response循環。您需要在循環之外聲明response。

你也想比較它，使用前String.Trim()從字符串修剪空白。否則，最後會出現換行符（\n），導致比較失敗。

string response; 

do { 
    //... 

    response = Console.ReadLine().Trim(); 
} while (response == "yes"); 

Answer 2

您的響應變量不在循環的上下文中。只需將變量聲明如下外循環：

 string response = String.Empty; 

     do 
     { 
      Console.WriteLine("enter a number between 1 and 5"); 
      int x = Convert.ToInt32(Console.ReadLine()); 

      Random r = new Random(); 
      int rr = r.Next(1, 5); 
      Console.WriteLine("Do you want to continue? Please select yes or no."); 
      response = Convert.ToString(Console.ReadLine()); 
     } while (response == "yes"); 

Answer 3

可能有助於封裝這個有點。如何：

static void Main(string[] args) 
    { 
     Random rand = new Random(); 
     do 
     { 
      Write("enter a number between 1 and 5"); 
      string response = Console.ReadLine(); 
      int x = 5; 
      if (Validate(response, "1-5")) int.TryParse(response, out x);     
      Write(rand.Next(0,x)); 
      Write("Do you want to continue? Please select yes or no.");     
     } while (Validate(Console.ReadLine().ToLower(), "yes")); 
    } 
    static void Write(string s) => Console.WriteLine(s); 
    static bool Validate(string s, string Pattern) => Regex.Match(s, Pattern).Success;