我試圖用一個列表視圖創建它的內部dialogfragment和我以前接受的答案,從這個問題做錯誤DialogFragment
How to display an existing ListFragment in a DialogFragment
但我得到一個Error inflating class fragment
時我嘗試打開片段對話框和應用程序崩潰
下面是dialog_fragment_with_list_fragment
佈局
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical" >
<fragment
android:id="@+id/flContent"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:padding = "10dp"
class="com.OptimusApps.stayhealthy.AndroidXMLParsingActivity" />
</LinearLayout>
,這是不是導致它失敗的androidxmlparsingactivity片段,我與其他碎片嘗試過了,他們沒有工作,要麼
下面是我的對話片段類
public class BodyDialogue extends DialogFragment {
int mNum;
/**
* Create a new instance of MyDialogFragment, providing "num"
* as an argument.
*/
static BodyDialogue newInstance(int num) {
BodyDialogue f = new BodyDialogue();
// Supply num input as an argument.
Bundle args = new Bundle();
args.putInt("num", num);
f.setArguments(args);
return f;
}
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
mNum = getArguments().getInt("num");
// Pick a style based on the num.
int style = DialogFragment.STYLE_NORMAL, theme = 0;
switch ((mNum-1)%6) {
case 1: style = DialogFragment.STYLE_NO_TITLE; break;
case 2: style = DialogFragment.STYLE_NO_FRAME; break;
case 3: style = DialogFragment.STYLE_NO_INPUT; break;
case 4: style = DialogFragment.STYLE_NORMAL; break;
case 5: style = DialogFragment.STYLE_NORMAL; break;
case 6: style = DialogFragment.STYLE_NO_TITLE; break;
case 7: style = DialogFragment.STYLE_NO_FRAME; break;
case 8: style = DialogFragment.STYLE_NORMAL; break;
}
switch ((mNum-1)%6) {
case 4: theme = android.R.style.Theme_Holo; break;
case 5: theme = android.R.style.Theme_Holo_Light_Dialog; break;
case 6: theme = android.R.style.Theme_Holo_Light; break;
case 7: theme = android.R.style.Theme_Holo_Light_Panel; break;
case 8: theme = android.R.style.Theme_Holo_Light; break;
}
setStyle(style, theme);
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
View view = inflater.inflate(R.layout.dialog_fragment_with_list_fragment, null);
return view;
}
}
這是怎麼我所說的dialogfragment
public void onClick(View v) {
BodyDialogue dialogFragment = BodyDialogue.newInstance(1);
dialogFragment .setRetainInstance(true);
dialogFragment .show(getFragmentManager(), "bodydialogue");
}
這是在logcat的原因
08-17 19:43:15.702: E/AndroidRuntime(3605): Caused by: java.lang.IllegalArgumentException: Binary XML file line #7: Duplicate id 0x7f0a0031, tag null, or parent id 0x0 with another fragment for com.OptimusApps.stayhealthy.AndroidXMLParsingActivity
08-17 19:43:15.702: E/AndroidRuntime(3605): at android.support.v4.app.FragmentActivity.onCreateView(FragmentActivity.java:285)
是的,因爲如果我只是叫它來代替一個片段,它看起來很好。就像我說的那樣,它與該片段無關,我在其他片段上測試過它們,並且它們也不工作,我添加了logcat,我認爲您可能會找到解決問題的方法 –
請不要在您的問題前加上字詞Android或任何其他標籤的標題,底部的標籤綽綽有餘。 – Luksprog