iOS定時器/工資計算器

Question

我正在製作一個計時器，它需要每小時的工資輸入並追蹤每秒鐘產生多少錢。定時器上的格式化工作得很好，但一旦硬幣達到99美元，它就會消失，只會增加美元。這是我得到的。

seconds = (int) (elapsedTime = (elapsedTime - (minutes *60))); 
pennies = seconds * (ratePerSecond * 100); 
if(pennies > 99){ 

    dollars++; 
    pennies = 0; 
} 

self.moneyDisplay.text = [NSString stringWithFormat: @"$%02d.%02d", dollars, pennies]; 

Answer 1

試試這個：

seconds = (int) (elapsedTime = (elapsedTime - (minutes *60))); 
pennies = seconds * (ratePerSecond * 100); 
float dollars = pennies/100.0; 
self.moneyDisplay.text = [NSString stringWithFormat: @"$%.2f", dollars]; 

或：

seconds = (int) (elapsedTime = (elapsedTime - (minutes *60))); 
pennies = seconds * (ratePerSecond * 100); 
int cents = pennies % 100; 
int dollars = pennies/100; 
self.moneyDisplay.text = [NSString stringWithFormat: @"$%02d.%02d", dollars, cents]; 

Answer 2

可能是你想這樣做（沒有，如果條件）：

dollars = pennies/100; 
pennies = pennies % 100; 
self.moneyDisplay.text = [NSString stringWithFormat: @"$%02d.%02d", dollars, pennies]; 

需要注意的是：％運算符的操作數sh都有整數類型。

希望這有助於.. :)