如何在Raphael JS中添加一個開放的三角形箭頭結束符?
最接近它的是塊全長,但我想在裏面做一個箭頭結尾。我怎樣才能添加一個開放的三角箭頭結束到一條線?
var path_1 = paper.path('M10 50 L250 50');
path_1.attr({stroke:'#FF0000', 'stroke-width': 6 ,'arrow-end': 'block-wide-long'});
如何在Raphael JS中添加一個開放的三角形箭頭結束符?
最接近它的是塊全長,但我想在裏面做一個箭頭結尾。我怎樣才能添加一個開放的三角箭頭結束到一條線?
var path_1 = paper.path('M10 50 L250 50');
path_1.attr({stroke:'#FF0000', 'stroke-width': 6 ,'arrow-end': 'block-wide-long'});
從raphael reference:上的路徑的端部
箭頭。字符串格式爲< type> [ - < width> [ - < length>]]。可能的類型:經典,塊,開放,橢圓形,菱形,無,寬度:...
因此,替代選項可能是open
。
var line = paper.path('M10 50 L250 50');
line.attr({stroke:'#FF0000', 'stroke-width': 6 ,'arrow-end': 'open-wide-long'});
見這裏:http://jsfiddle.net/Ljoe1rpw/2/
如果你想用一個空的三角形,你將不得不修改拉斐爾源。
我設法通過修改拉斐爾圖書館來創建開放的三角形箭頭。
近線3769添加一個標記:
markers = {
block: "M5,0 0,2.5 5,5z",
**opentriangle: "M5,1 2,2.5 5,4z",**
classic: "M5,0 0,2.5 5,5 3.5,3 3.5,2z",
diamond: "M2.5,0 5,2.5 2.5,5 0,2.5z",
open: "M6,1 1,3.5 6,6",
oval: "M2.5,0A2.5,2.5,0,0,1,2.5,5 2.5,2.5,0,0,1,2.5,0z"
},
近線3907修改while循環:
while (i--) {
switch (values[i]) {
case "block":
**case "opentriangle":**
case "classic":
case "oval":
case "diamond":
case "open":
case "none":
type = values[i];
break;
case "wide": h = 5; break;
case "narrow": h = 2; break;
case "long": w = 5; break;
case "short": w = 2; break;
}
}
近線4995修改while循環:
while (i--) {
switch (values[i]) {
case "block":
**case "opentriangle":**
case "classic":
case "oval":
case "diamond":
case "open":
case "none":
type = values[i];
break;
case "wide":
case "narrow": h = values[i]; break;
case "long":
case "short": w = values[i]; break;
}
}
近線3925加入否則如果封鎖:
if (type == "open") {
w += 2;
h += 2;
t += 2;
dx = 1;
refX = isEnd ? 4 : 1;
attr = {
fill: "none",
stroke: attrs.stroke
};
}
**else if(type == "opentriangle"){
w += 5;
h += 5;
dx = 7;
refX = 0;
attr = {
fill: "none",
stroke: attrs.stroke,
};
}**
else {
refX = dx = w/2;
attr = {
fill: attrs.stroke,
stroke: "none"
};
}
很酷。好的解決方案+1 – RodrigoDela 2015-02-15 08:08:53
確實,我需要一個空的三角形。 – varespuuotsas 2015-02-14 15:53:04