閱讀JSON數據帶有PHP令牌

Question

如何使用PHP讀取JSON數據響應？

這是代碼：

$response = Unirest\Request::get("https://montanaflynn-spellcheck.p.mashape.com/check/?text=This+sentnce+has+some+probblems.", 
    array(
    "X-Mashape-Key" => "MY X-Mashape-Key", 
    "Accept" => "application/json" 
) 
); 

，並給我這個JSON數據：

{ 
    "original": "This sentnce has some probblems.", 
    "suggestion": "This sentence has some problems.", 
    and ... 
} 

我想在URL返回 「suggestion」 與$

這是一個例子：

$user_id = '123456789' 
$mytext = '?' // I WANT RETURN "suggestion" HERE ! 

$url = 'https://api.telegram.org/mytoken/sendMessage?chat_id='.$user_id.'&text='.$mytext 
file_get_contents($url); 

Answer 1

您可以使用json_decode（）。

參見： http://php.net/manual/en/function.json-decode.php

你只需要做：

$response = json_decode($response,1); 
echo $response['suggestion']; 

設置json_decode的）到1（真）的第二個參數（將返回JSON數據的關聯數組。

如果你想用你的代碼示例，包括它的URL：

$user_id = '123456789' 
$json = json_decode($response,1); 
$mytext = $json['suggestion']; 

$url = 'https://api.telegram.org/mytoken/sendMessage?chat_id='.$user_id.'&text='.$mytext 
file_get_contents($url); 

Answer 2

使用json_decode將json_response轉換爲array.Add第二個參數'true'使其成爲您應該熟悉的數組。

通過指定訪問建議變量。

$response = Unirest\Request::get("https://montanaflynn-spellcheck.p.mashape.com/check/?text=This+sentnce+has+some+probblems.", 
    array(
    "X-Mashape-Key" => "MY X-Mashape-Key", 
    "Accept" => "application/json" 
) 
); 
$data=json_decode($response,true); 
$url = 'https://api.telegram.org/mytoken/sendMessage?chat_id='.$user_id.'&text='.$data['suggestion']; 
echo $url;