python raw_input忽略換行

Question

有沒有辦法忽略通過raw_input輸入的數據中的換行符？我正在嘗試使用raw_input來輸入從電子表格複製並粘貼的字符串列表。問題在於看起來新的行字符會導致數據提前輸入。所有的空白空間都將被剝離，因此在輸入數據時刪除換行符會帶來額外的好處。這些數據需要直接通過終端提示輸入，而不是從文件中讀取。

這是我迄今所做的：一旦

names = raw_input('Shoot me some names partner: ') 

print 'What do you want to do?' 
print '1 - format names for program 1' 
print '2 - format names for program 2' 

first_act = raw_input('Enter choice: ') 

print names 
print first_act 

現在，當我運行這個輸入我投入了谷歌文檔電子表格中的假名字來測試，因爲我按下Shift + CTL + V ，沒有擊中輸入我得到這個：

seth@linux-1337:~> python pythonproj/names.py 
Shoot me some names partner: abcd,efg,hijkl,mnop 
abcd,efg,hijkl,mnop 
abcd,efg,hijkl,mnop 
abcd,efg,hijkl,mnop 
abcd,efg,hijkl,mnop 
abcd,efg,hijkl,mnop 
abcd,efg,hijkl,mnop 
abcd,efg,hijkl,mnopWhat do you want to do? 
1 - format names for program 1 
2 - format names for program 2 
Enter choice: abcd,efg,hijkl,mnop 
abcd,efg,hijkl,mnop 
seth@linux-1337:~> abcd,efg,hijkl,mnop 
If 'abcd,efg,hijkl,mnop' is not a typo you can use command-not-found to lookup the package that contains it, like this: 
cnf abcd,efg,hijkl,mnop 
seth@linux-1337:~> abcd,efg,hijkl,mnop 
If 'abcd,efg,hijkl,mnop' is not a typo you can use command-not-found to lookup the package that contains it, like this: 
cnf abcd,efg,hijkl,mnop 
seth@linux-1337:~> abcd,efg,hijkl,mnop 
If 'abcd,efg,hijkl,mnop' is not a typo you can use command-not-found to lookup the package that contains it, like this: 
cnf abcd,efg,hijkl,mnop 
seth@linux-1337:~> abcd,efg,hijkl,mnop 
If 'abcd,efg,hijkl,mnop' is not a typo you can use command-not-found to lookup the package that contains it, like this: 
cnf abcd,efg,hijkl,mnop 
seth@linux-1337:~> abcd,efg,hijkl,mnop 
If 'abcd,efg,hijkl,mnop' is not a typo you can use command-not-found to lookup the package that contains it, like this: 
cnf abcd,efg,hijkl,mnop 
seth@linux-1337:~> abcd,efg,hijkl,mnop 

我很新的python，我不是迄今爲止最有經驗的程序員。這是python 2.7。

Answer 1

我不確定你想問什麼，但是當你使用raw_input（）時，它會去掉尾隨的換行符。

而醫生說也一樣。

如果提示參數存在，則將其寫入標準輸出 而不會出現尾隨換行符。該函數然後從輸入中讀取一行， 將其轉換爲字符串（剝離尾隨換行符），並返回 。讀取EOF時，引發EOFError。

Answer 2

因爲raw_input只需要一條線從輸入你需要創建一個循環：

names = [] 
print('Shoot me some names partner: ') 
while True: 
    try: 
     name = raw_input() 
    except KeyboardInterrupt: 
     break 
    names.append(name) 

print('What do you want to do?') 
print('1 - format names for program 1') 
print('2 - format names for program 2') 

first_act = raw_input('Enter choice: ') 

print(names) 
print(first_act) 

試運行：

Shoot me some names partner: 
name1 
name2 
^CWhat do you want to do? 
1 - format names for program 1 
2 - format names for program 2 
Enter choice: 1 
['name1', 'name2'] 
1 

注意我用^C（按Ctrl-C）這裏以指示輸入的結束。